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sleet_krkn [62]
3 years ago
13

Please solve this geo problem

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Step-by-step answer:

The first step in solving a problem of geometry and trigonometry is to draw a diagram, with all the given information in it.  The attached image does just that.

Here, we have (horizontal) distance of building to the tower is 400'.

We see two right triangles, each with a leg of 400' (horizontal).

The vertical distances are denoted h1 and h2 for the angles of elevation 24 and 20 degrees respectively.

Using the definition of tangent, we have

h1= 400tan24=178.1

h2=400tan20=145.6

The height of the tower is therefore h1+h2=178.1+145.6=323.7 feet

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Complete Question

A hypothetical population consists of eight individuals ages 13 14 17 20 21 22 24 30 years.  

A: what is the probability that a person in this population is a teenager?  

B: what is the probability of selecting a participant who is at least 20 years old?

We have that  probability that a person in this population is a teenager and probability of selecting a participant who is at least 20 years old is

From the question we are told

A hypothetical population consists of eight individuals ages 13, 14, 17, 20, 21, 22, 24, & 30 years.

  • P(T)=0.38
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Generally the equation for the  probability that a person in this population is a teenager   is mathematically given as

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b)

Generally the equation for the probability of selecting a participant who is at least 20 years old  is mathematically given as

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A manufacturer of prefabricated homes has decided to subcontract four components of the homes. Several companies are interested
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Answer:

Following are the solution to the given question:

Step-by-step explanation:

Let x_{ij}=1 when i is the element itself is allocated to 'j' i_0

Min  

185X_{1A}+225X_{1B} +193X_{1C} +207X_{1D} +200X_{2A} +190X_{2B} +175X_{2C}+225X_{2D}+330X_{3A} +320X_{3B} +315X_{3C}+300X_{3D}+375X_{4A}+389X_{4B}+425X_{4C}+ 445X_{4D}

Subject to:

X_{1A} +X_{1B}+X_{1C}+X_{1D}=1\\\\X_{2A} +X_{2B}+X_{2C}+X_{2D}=1\\\\X_{3A} +X_{3B}+X_{3C}+X_{3D}=1\\\\X_{4A} +X_{4B}+X_{4C}+X_{4D}=1\\\\X_{1A} +X_{2A}+X_{3A}+X_{4A}=1\\\\X_{1B} +X_{2B}+X_{3B}+X_{3B}=1\\\\X_{1C} +X_{2C}+X_{3C}+X_{4C}=1\\\\X_{1D} +X_{2D}+X_{3D}+X_{4D}=1

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