Answer:
A intersection B or A Π B
Step-by-step explanation:
The intersection of A and B is the set of all those elements which belong to both A and B.
Answer:
a) Cosine function
b) amplitude=1
c) Period=π, b=2
d) y=0
e)
Step-by-step explanation:
a)Since the graph is symmetric with respect to the y-axis, it is a cosine function. This time the cosine function is reflected in the x-axis.
b) The graph ranges between -1 and 1, therefore we have the amplitude to be |-1|=|1|=1
c) The graph completes one full cycle within every π units. Therefore the time period is π. Also the value of b is 2, because the graph repeats twice on the interval [0,2π]
d) The midline divides the graph into two equal halves.
The midline has equation y=0.
e) The equation of this graph is of the for m,
where a=1 is the amplitude and b=2 is the frequency.
Therefore the equation is :
Answer:
Reflectional symmetry with one line of symmetry
Step-by-step explanation:
You can add a line of symmetry right down the middle that would make the left and right of the figure symmetrical, so it is reflectional with one line of symmetry.
Answer:
(x)^2 (y)^2
---------- + --------- = 1
4 3
Step-by-step explanation:
The standard equation for an ellipse is
(x-h)^2 (y-k)^2
---------- + --------- = 1
a^2 b^2
The center is at (h,k)
The vertices are at (h±a, k)
The foci are at (h±c,k )
Where c is sqrt(a^2 - b^2)
It is centered at the origin so h,k are zero
(x)^2 (y)^2
---------- + --------- = 1
a^2 b^2
The center is at (0,0)
The vertices are at (0±a, 0)
The foci are at (0±c,0 )
The vertices are (±2,0) so a =2
The foci is 1
c = sqrt(a^2 - b^2)
1 = sqrt(2^2 - b^2)
Square each side
1 = 4-b^2
Subtract 4 from each side
1-4 = -b^2
-3 = -b^2
3= b^2
Take the square root
b=sqrt(3)
(x)^2 (y)^2
---------- + --------- = 1
4 3