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ikadub [295]
3 years ago
7

Which is the area of a rectangle with a length of 21 feet and a width of 15 feet?Select one of the options below as your answer:

A. 35 square yards B. 36 square yards C. 50 square yards D. none of the above
Mathematics
2 answers:
raketka [301]3 years ago
7 0
Pretty sure its D. Area formula is Length x Width so 21 x 15 is 1175 or around there. (Going off my head.)
Stells [14]3 years ago
5 0

Answer:

A ) Area of rectangle = 35 square yard.

Step-by-step explanation:

Given : length of 21 feet and a width of 15 feet.

To find : Which is the area of a rectangle .

Solution : We have given

Length = 21 feet.

Width = 15 feet.

We need to find area in yard so, we will convert feet in to yard.

1 feet = 0.3333 yard

21 feet = 7 yard.

15 feet = 5 yard.

Length = 7 yard.

Width = 5 feet .

Area = length * width .

Area of rectangle = 7  * 5

Area of rectangle = 35 square yard.

Therefore, A ) Area of rectangle = 35 square yard.

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3 years ago
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Consider the two expressions 4b(b+1) and (2b+7)(2b-8). Compare their values if b=-3, b=-2, and if b=10. Is it true that for an v
frutty [35]

Answer:

FIRST EXPRESSION:

-  If b=-3, the value of 4b(b+1) is  24

-  If b=-2, the value of 4b(b+1) is  8

- If b=10, the value of 4b(b+1) is  440

 SECOND EXPRESSION:

-  If b=-3, the value of (2b+7)(2b-8)) is  -14

-  If b=-2, the value of (2b+7)(2b-8)) is  -36

- If b=10, the value of (2b+7)(2b-8)) is  324

Yes, for any value of "b" the value of the first expression is greater than the value of the second expression.

Step-by-step explanation:

Substitute the given values of "b" into each expression and evaluate.

- For the first expression 4b(b+1), you get:

If b=-3 → 4(-3)(-3+1)=24

If b=-2 → 4(-2)(-2+1)=8

 If b=10 → 4(10)(10+1)=440

 - For the second expression (2b+7)(2b-8)), you get:

If b=-3 → (2(-3)+7)(2(-3)-8)=-14

If b=-2 → (2(-2)+7)(2(-2)-8)=-36

 If b=10 → (2(10)+7)(2(10)-8)=324

You can observe that for any value of "b" the value of the first expression is greater than the value of the second expression.

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