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SpyIntel [72]
3 years ago
5

Solve for x and y2x+3yi=-14+9i

Mathematics
1 answer:
ryzh [129]3 years ago
4 0
2,314 is the anwser

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If g || h and m∠2 = 110 what is m∠6\
Kamila [148]
The answer is 7 ok hduehdhd
8 0
3 years ago
what is the area of the shaded sector of the circle if the radius is 14 ft? leave your answer in terms of pi
Strike441 [17]

Given:

Radius = 14 ft

θ = 45°

To find:

Area of the shaded sector

Solution:

Area of the sector formula:

$\text { area of sector }=\frac{\theta}{360^{\circ}} \times \pi r^{2}

                      $=\frac{45^\circ}{360^{\circ}} \times \pi \times 14^{2}

                      $=\frac{1}{8} \times \pi \times 196

                      =24.5\pi ft²

The area of the shaded sector of a circle is 24.5π ft².

3 0
3 years ago
Find an equation of variation in which y varies directly as x and y=1 when x=0.5. Then find the value of y when x = 14.
FromTheMoon [43]

<u>Part 1</u>

The value of y is twice that of x, so the equation is y = 2x.

<u>Part 2</u>

Substituting in x = 14, we get y = 2(14) = 28.

8 0
1 year ago
Which expression is equivalent to 4(3+5)-3.94?
kondor19780726 [428]

Answer:

4(3+5)-3.94

4(8)-3.94

32 - 3.94

what do you mean by . multifaction or decimal

Step-by-step explanation:

3 0
3 years ago
At Clucker's Chicken, a bucket of 4 pieces of dark meat and 5 pieces of white meat costs 7.05. A bucket of 3 pieces of dark meat
Alenkinab [10]

Answer:

The cost of a piece of dark meat is <u>$0.70</u> and the cost of a piece of white meat is <u>$0.85</u>.

Step-by-step explanation:

Given:

At Clucker's Chicken, a bucket of 4 pieces of dark meat and 5 pieces of white meat costs 7.05.

A bucket of 3 pieces of dark meat and 8 pieces of white meat costs 8.90.

Now, to find the cost of a piece of dark meat and the cost of a piece of white meat.

Let the cost of a piece of dark meat be x.

And the cost of a piece of white meat be y.

A bucket of 4 pieces of dark meat and 5 pieces of white meat costs $7.05.

So,

4x+5y=7.05

4x=7.05-5y  

x=\frac{7.05-5y}{4}   .......(1)

Now, a bucket of 3 pieces of dark meat and 8 pieces of white meat costs $8.90.

3x+8y=8.90

Substituting the value of x from equation (1) we get:

3(\frac{7.05-5y}{4})+8y=8.90

\frac{21.15-15y}{4} +8y=8.90

\frac{21.15-15y+32y}{4} =8.90

<em>Multiplying both sides by 4 we get:</em>

21.15-15y+32y=35.60

21.15+17y=35.60

<em>Subtracting both sides by 21.15 we get:</em>

17y=14.45

<em>Dividing both sides by 17 we get:</em>

y=0.85

<u>The cost of a piece of white meat = $0.85.</u>

Now, substituting the value of y in equation (1) we get:

x=\frac{7.05-5y}{4}

x=\frac{7.05-5\times 0.85}{4}

x=\frac{7.05-4.25}{4}

x=\frac{2.8}{4}

x=0.70.

<u>The cost of a piece of dark meat = $0.70.</u>

Therefore, the cost of a piece of dark meat is <u>$0.70</u> and the cost of a piece of white meat is <u>$0.85</u>.

5 0
3 years ago
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