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ratelena [41]
3 years ago
14

A company makes 3 types of cable. cable a requires 3 black, 3 white, and 2 red wires. b requires 1 black, 2 white, and 1 red. c

requires 2 black, 1 white, and 2 red. they used 95 black, 100 white and 90 red wires. how many of each cable were made?

Mathematics
1 answer:
gavmur [86]3 years ago
6 0
Check the attached file for the answer.

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Figure ABCD is reflected over the x-axis to create figure PQRS. What are the coordinates of point Q?​
Mekhanik [1.2K]

Answer:

Q = (1, -5)

Step-by-step explanation:

Reflection over x-axis (x,y) → (x,-y)

B = (1,5)

Q = (1,-5)

4 0
3 years ago
A. Find the mean median and mode of the data.
IrinaK [193]
26 26 29 30 31 33 33 33 34 34 70

A.
Mean:30.9
Add all numbers up and divide by however many there are.
Median:32
Number in the middle spot
Mode:33
Number that occurs the most

B.
Mean:34.45
Median:33
Mode:33
4 0
3 years ago
How many of the scores from the group that studied in question eight are in one mean absolute deviation of the mean? Which score
n200080 [17]

Answer:

93

Step-by-step explanation:

<u><em>Add all of the numbers and divide them by the number of numbers there are.


</em></u><em>Hope this helped  ·ω·</em>

4 0
3 years ago
The midpoint of AB is M (2,0). If the coordinates of A are, (-3, 3), what are the coordinates of B?​
gregori [183]

Given:

M is the midpoint of AB.

M(2,0) and A(-3, 3).

To find:

The coordinates of point B.

Solution:

Midpoint formula:

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Let the coordinates of point B are (a,b). Then, using the midpoint formula, we get

(2,0)=\left(\dfrac{-3+a}{2},\dfrac{3+b}{2}\right)

On comparing both sides, we get

\dfrac{-3+a}{2}=2

-3+a=2\times 2

a=4+3

a=7

And,

\dfrac{3+b}{2}=0

3+b=0

3+b-3=0-3

b=-3

Therefore, the coordinates of point B are (7,-3).

5 0
3 years ago
According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating
Natali [406]

Answer:

a) Null and alternative hypothesis

H_0: \mu=32.48\\\\H_a:\mu< 32.48

b) Test statistic t=-1.565

P-value = 0.0612

NOTE: the sample size is n=65.

c) Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

d) Null and alternative hypothesis

H_0: \mu=32.48\\\\H_a:\mu< 32.48

Test statistic t=-1.565

Critical value tc=-1.669

t>tc --> Do not reject H0

Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Then, the null and alternative hypothesis are:

H_0: \mu=32.48\\\\H_a:\mu< 32.48

The significance level is 0.05.

The sample has a size n=65.

The sample mean is M=30.15.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{12}{\sqrt{65}}=1.4884

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{30.15-32.48}{1.4884}=\dfrac{-2.33}{1.4884}=-1.565

The degrees of freedom for this sample size are:

df=n-1=65-1=64

This test is a left-tailed test, with 64 degrees of freedom and t=-1.565, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t

As the P-value (0.0612) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

<u>Critical value approach</u>

<u></u>

At a significance level of 0.05, for a left-tailed test, with 64 degrees of freedom, the critical value is t=-1.669.

As the test statistic is greater than the critical value, it falls in the acceptance region.

The null hypothesis failed to be rejected.

6 0
3 years ago
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