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3 years ago

Write the equation g(x) of the transformation of the parent graph f(x) = |x| stretched horizontally by a factor of 3.

Mathematics

2 answers:

Anni [7]3 years ago

4 0

Answer:

g(x) = |1/3x|

Step-by-step explanation:

f(x) = |x|

y = f(Cx) 0 < C < 1 stretches it in the x-direction

g(x) = |1/3x|

Ainat [17]3 years ago

4 0

We can start with: f(x) = |x|

0 < c < 1 means x-direction stretch

y = f(cx)

3 unit horizontal stretch

After: g(x) = |1/3x|

Best of Luck!

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Can someone pls answer 150 divided by 30

Svetlanka [38]

Answer:

Step-by-step explanation:

150/30 = 15/3 = 5

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3 years ago

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sukhopar [10]

35
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2 years ago

The national average sat score (for verbal and math) is 1028. if we assume a normal distribution with standard deviation 92, wha

elena55 [62]

Let X be the national sat score. X follows normal distribution with mean μ =1028, standard deviation σ = 92

The 90th percentile score is nothing but the x value for which area below x is 90%.

To find 90th percentile we will find find z score such that probability below z is 0.9

P(Z <z) = 0.9

Using excel function to find z score corresponding to probability 0.9 is

z = NORM.S.INV(0.9) = 1.28

z =1.28

Now convert z score into x value using the formula

x = z *σ + μ

x = 1.28 * 92 + 1028

x = 1145.76

The 90th percentile score value is 1145.76

The probability that randomly selected score exceeds 1200 is

P(X > 1200)

Z score corresponding to x=1200 is

z = $\frac{x - mean}{standard deviation}$

z = $\frac{1200-1028}{92}$

z = 1.8695 ~ 1.87

P(Z > 1.87 ) = 1 - P(Z < 1.87)

Using z-score table to find probability z < 1.87

P(Z < 1.87) = 0.9693

P(Z > 1.87) = 1 - 0.9693

P(Z > 1.87) = 0.0307

The probability that a randomly selected score exceeds 1200 is 0.0307

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3 years ago

Find the standard deviation of the data, 12, 19, 9.

jek_recluse [69]

Answer:

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Step-by-step explanation:

Find the mean:

$\text{Mean}=\frac{12+19+9}{3}=\frac{40}{3}$

Find the standard deviation:

$\text{Standard Deviation}=\sqrt{\frac{(12-\frac{40}{3})^2+(19-\frac{40}{3})^2+(9-\frac{40}{3})^2}{3}}=\sqrt{\frac{158}{9}}\approx4.19$

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2 years ago

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velikii [3]

I’m pretty sure it’s c , sorry if it’s wrong tho

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3 years ago