The answer is 185 ft 2.
Since it is a parralellogram you have to multiply the base x height.
And it has a 2 right next to it because you multiplied base x height
Hope it helps!~
A 50% increase followed by a 33% decrease leaves you with a constant 17% increase. It is less than the original.
Answer:
70 cards
Step-by-step explanation:
Let A = the number of Andys cards
J = the number of Jons cards
Jon and Andy had a total of 560 trading cards
A+J = 560
After Jon gave 1/9 of his trading cards to Andy, they has an equal number of trading cards
J - 1/9 J = 1/9 J +A
Combine like terms
8/9 J = 1/9 J +A
Subtract 1/9J from each side
7/9J = A
Substitute this into A +J = 560
7/9J +J = 560
Combine like terms
7/9J +9/9J = 560
16/9 J = 560
Multiply each side by 9/16
9/16 *16/9 J = 560 *9/16
J =315
Jon originally had 315 cards
Now we need to find Andys cards
7/9J = A
7/9 (315) =A
245=A
How many more trading cards did Jon have that Andy in the beginning?
We need to take Jons cards and subtract Andys cards
J-A
315-245
70
Answer:
137.5 Miles
Step-by-step explanation:
Time driven=5/2 hours
Miles per hour=55
55 times 5/2= 137.5 miles
So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

Next, square both sides:

Next, subtract x and add 2 to both sides of the equation:

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

Now you can rewrite the equation as 
Now, apply the Zero Product Property and solve for x as such:

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>