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Marina86 [1]
3 years ago
15

The questions are in the picture

Mathematics
2 answers:
zheka24 [161]3 years ago
8 0

Answer:

Q1 is D Q2 is A Q3 is C

Step-by-step explanation:

o-na [289]3 years ago
4 0

Answer:

I can't see the picture

Step-by-step explanation:

I can't see it

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A colony of bacteria is grown under ideal conditions in a laboratory so that the population increases exponentially with time. A
Naddik [55]

Answer:

Initial bacterias = 6006000

Altought I believe is safe to assume that the values were 192,000 and 384,000 instead of 192,192,000 and 384,384,000, in that case the initial bacterias is 6000

Step-by-step explanation:

A exponential growth follows this formula:

Bacterias  = C*rⁿ

C the initial amount

r the growth rate

n the number of time intervals

Bacterias (55 hours) = 192,192,000

Bacterias (66 hours) = 384,384,000

Bacterias(55hours)=C*r^{{\frac{55-t}{t}}} \\Bacterias (66hours) = C*r^{\frac{66-t}{t}}}

If you divide both you can get the growth rate:

\frac{Bacterias (66hours)}{Bacterias(55hours)}=\frac{C*r^{\frac{66-t}{t}}}{C*r^{{\frac{55-t}{t}}}} \\\frac{384,384,000}{192,192,000} =r^{\frac{66-t}{t} -\frac{55-t}{t} } \\2 =r^{\frac{11}{t}}

So with that r = 2 and each time interval correspond to 11 years

Then replacing in one you can get the initial amount of C

Bacterias (55hours)=C*2^{\frac{55-11}{11} } 192,192,000 = C*32\\C= 6006000

7 0
3 years ago
What is the scale factor in the dilation?
vlada-n [284]

Answer:

3

Step-by-step explanation:

Look at how the x values gets multiplied by 3

6 0
3 years ago
A person owes a debt of $10
AleksandrR [38]
So the person is out of pocket of $10.00
6 0
3 years ago
What is the solution of the system pf equations y=-4x+6 y= -5x - 4
kakasveta [241]

that's the solution of the system

6 0
3 years ago
Read 2 more answers
Consider the following pair of equations: y = −2x + 8 y = x − 1 Explain how you will solve the pair of equations by substitution
Rzqust [24]
Y = -2x +8
y = x-1

y=y

-2x+8 = x-1

-3x = -1 -8

-3x = -9

3x = 9

x = 3


 
6 0
3 years ago
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