Question

Write the expression as a single logarithm

Answer 1

1/2 [3logx + logy]

Step 1:

we use the property of n logx =log xⁿ for 3 logx

so 1/2[3logx +logy]= 1/2 [log x³ + log y]

Step 2:

We use another property here log a + log b = log (ab)

1/2[log x³y]

Step 3:

we again use the property of n logx =log xⁿ, bringing 1/2 in power

[log x³y]^1/2

√log(x³y)