Question

In the first week of August, there were 1,060 people at an amusement

Answer 1

Answer:

In second week there is percentage decrease (-ve sign) of 20% in people visiting compare to first week.

In third week there is percentage increase of 50% in people visiting compare to second week.

In fourth week there is percentage decrease of 75% in people visiting compare to third week.

Solution:

Need to determine percentage change in the number of people who went to amusement park for each week in august.

Given that,

In first week of august number of people went to amusement park let say $p_1$ = 1060

In second week of august number of people went to amusement park let say $p_2$ = 848

In third week of august number of people went to amusement park let say $p_3$ = 1272

And in fourth week of august number of people went to amusement park let say $p_4$ = 318

Percentage change from first week to second week is as follows

$\% \text { change }=\frac{p_{2}-p_{1}}{p_{1}} \times 100=\frac{848-1060}{1060} \times 100$

$=\frac{-212}{1060} \times 100=-20 \%$

So in second week there is percentage decrease (-ve sigh) of 20% in people visiting compare to first week.

Percentage change from second week to third week is as follows

$\begin{aligned} \% \text { change }=\frac{p_{3}-p_{2}}{p_{2}} \times 100 &=\frac{1272-848}{848} \times 100 =\frac{424}{848} \times 100=50 \% \end{aligned}$

So in third week there is percentage increase of 50% in people visiting compare to second week

Percentage change from third week to fourth week is as follows

$\begin{aligned} \% \text { change }=& \frac{p_{4}-p_{3}}{p_{3}} \times 100=\frac{318-1272}{1272} \times 100 =\frac{-954}{1272} \times 100=-75 \% \end{aligned}$

So in fourth week there is percentage decrease of 75% in people visiting compare to third week