A rectangle with a perimeter of 54 cm could have which dimensions

2 answers:

8 0

Here are the possibilities:
20 cm by 7 cm. (20+20+7+7)
15 cm by 12 cm. (15+15+12+12)
16 cm by 11 cm. (16+16+11+11)
18 cm by 9 cm. (18+18+9+9)
17 cm by 10 cm. (17+17+10+10)

These are just the most likely possibilities.

melomori [17]4 years ago

7 0

8 and 19, because 2 times the length + 2 times the width = 54 :)

You might be interested in

The legs of a right triangle are x and 15 while the hypotenuse is 17.

Deffense [45]

Answer:

Since the Option of equation are not given. Kindly chose any of the below equation from the answer to find the value of 'x'.

$x^2+15^2=17^2$

$x^2=17^2-15^2$

$x^2+225=289$

$x^2=289-225$

Step-by-step explanation:

Given:

Length of One leg = x

Length of other Leg= 15

Hypotenuse = 17

We need to find the equation used to determine the value of x.

Solution:

Assuming Triangle to right angled triangle.

So we will apply Pythagoras theorem which sates that;

"The square of sum of two legs of right angle triangle is equal to square of the length of hypotenuse."

so we can say that;

$x^2+15^2=17^2$

$x^2=17^2-15^2$

$x^2+225=289$

$x^2=289-225$

Since the equation are not given. Kindly chose any of the below equation from the answer to find the value of 'x'.

$x^2+15^2=17^2$

$x^2=17^2-15^2$

$x^2+225=289$

$x^2=289-225$

5 0

3 years ago

What is 8.57x10-⁴ in standered form ?

marusya05 [52]

Kaleerain5,

In order to get your answer you must remember that if the exponent is negative move to the left and if the exponent is positive you have to move to the right.