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3 years ago

What is an equivalent expression for 40+36

1 answer:

7 0

An equiavalent expression for 40+36 can be:

46+30
50+26
etc.

As long as the expression equals 76, it is correct

hope this helps

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There are 25 pineapples in a basket. Each pineapple weighs 100 grams. What is the total weight off all the pineapples in the bas

Lady_Fox [76]

The total weight is 2500 grams. 25 x 100 = 2500

5 0

3 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

7 0

3 years ago

Tyler is simplifying the expression 6 - 2x + 5 + 4x. Here is his work.

tangare [24]

Line B is incorrect cause he did not do like terms

6 0

3 years ago

If a football is thrown upward, its height above the

dybincka [34]

Answer:

a) s = -16 $t^{2}$ + 192t + 96

b) Height of the football after 2 seconds is 448 feet.

ii. The football would not hit the ground after 2 seconds.

Step-by-step explanation:

Given:

s = -16 $t^{2}$ + $V_{o}$ t + $s_{o}$

where: s is the height of the football above the ground, t is the time, $V_{o}$ is the initial velocity and $s_{o}$ is the initial height.

The height of the building = $V_{o}$ = 192 feet and the initial speed of the ball = $s_{o}$ = 96 feet per second, then;

s = -16 $t^{2}$ + 192t + 96

a) The polynomial is given as:

s = -16 $t^{2}$ + 192t + 96

b) The height of the football when t = 2 seconds is;

s = -16(2) + 192(2) + 96

= -32 + 384 + 96

= -32 + 480

s = 448

The height of the football when t = 2 seconds is 448 feet.

ii. The football would not hit the ground after 2 seconds.

7 0

3 years ago

Plz help with this 30 points no fake! Question number four

IceJOKER [234]

1.6 & 3.784 hope this helped

7 0

3 years ago