Answer:
isn't a fortnight 14?
Step-by-step explanation:
Answer:
-5,-8,-11,-14,-17
Step-by-step explanation:
-3n -2
n=1 -3(1) -2 = -3-2 = -5
n=2 -3(2) -2 = -6-2 = -8
n=3 -3(3) -2 = -9-2 = -11
n=4 -3(4) -2 = -12-2 = -14
n=5 -3(5) -2 = -15-2 = -17
(6a+11)=(2a+83)
6a+11=2a+83
-11 -11
6a=2a+72
-2a -2a
4a=72
4/4a=72/4
a=18
The solution is 18
<h3>3
Answers:</h3>
A) y intercept is (0,3)
C) Axis of symmetry is x = -1
D) Vertex is (-1, 4)
So basically everything but choice B is true.
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Explanation:
Choice A is true because plugging in x = 0 leads to y = 3. Effectively, anything with an x goes away when x = 0 leaving that 3 behind. So finding the y intercept in this form is fairly fast.
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To check choices B through D, let's convert the equation into vertex form.
y = -1x^2 - 2x + 3 is in the form y = ax^2 + bx + c where
a = -1
b = -2
c = 3
The vertex is located at (h,k) such that h = -b/(2a)
Plug the values of 'a' and 'b' into the equation below
h = -b/(2a)
h = -(-2)/(2*(-1))
h = 2/(-2)
h = -1
The x coordinate of the vertex is x = -1
Then use this to find the y coordinate of the vertex
y = -1x^2 - 2x + 3
y = -1(-1)^2 - 2(-1) + 3
y = 4
The y coordinate of the vertex is 4, meaning k = 4
The vertex overall is (h,k) = (-1, 4)
This shows choice D is true, meaning choice B has to be false.
Choice C is true because the axis of symmetry is the x coordinate of the vertex. This is the vertical line that cuts the parabola into two mirrored halves. This vertical line always goes through the vertex.
