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4 years ago

What's 2 (n+3) in words

Mathematics

2 answers:

baherus [9]4 years ago

6 0

two times a number n plus three

Naya [18.7K]4 years ago

3 0

Since the 2 multiplies the whole parenthesis, you have to add n and 3, and then double the whole result.

For example, if $n=6$ , you first have to perform $6+3=9$ , and then double the result: $2\times 9 = 18$

So, in words, you can descrive this steps as "twice the sum of a number n and 3"

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If (0, 2) maps onto (-3, -5), then (8, 5) maps onto _____?

Allisa [31]

I think it would be (5,-2)

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4 years ago

9. Consider the circles with the following equations:

kenny6666 [7]

Answer with Step-by-step explanation:

We are given that

$x^2+y^2=(\sqrt 2)^2$

$(x-3)^2+(y-3)^2=32=(4\sqrt 2)^2$

Compare with the equation of circle

$(x-h)^2+(y-k)^2=r^2$

Where center of circle=(h,k)

r=Radius of circle

a.Center of circle=(0,0)

Radius= $\sqrt 2$ units

Center of second circle=(3,3)

Radius of second circle= $4\sqrt 2$ units

b.Distance formula: $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Using the formula

The distance between the centers of two circle

= $\sqrt{(3-0)^2+(3-0)^2}=3\sqrt 2$

Hence, the distance between the centers of two circle = $3\sqrt 2$ units.

Substitute x=-1 and -1

$1+1=2=$

$(1-3)^2+(1-3)^2=32$

The circle must be tangent because there is just one point (-1,-1) is common in both circles and satisfied the equations of circle.

8 0

3 years ago

Find the expansions of sin⁡5θ and cos⁡5θ in terms of sin⁡θ and cos⁡θ.

qwelly [4]

$\bf \textit{quad-angle identities}\\\\\\

cos(4\theta)=8cos^4(\theta)-8cos^2(\theta)+1
\\\\\\
sin(4\theta)=
\begin{cases}
8sin(\theta)cos^3(\theta)-4sin(\theta)cos(\theta)\\\\
4sin(\theta)cos(\theta)-8sin^3(\theta)cos(\theta)
\end{cases}\\\\
-----------------------------\\\\
$

$\bf sin(5\theta)\iff sin(4\theta + \theta)
\\\\\\
sin(4\theta)cos(\theta)+cos(4\theta)sin(\theta)
\\\\\\\
[4sin(\theta)cos(\theta)-8sin^3(\theta)cos(\theta)]cos(\theta)\\\\ + [8cos^4(\theta)-8cos^2(\theta)+1]sin(\theta)$

$\bf -----------------------------\\\\
cos(5\theta)\iff cos(4\theta + \theta)
\\\\\\
cos(4\theta)cos(\theta)-sin(4\theta)sin(\theta)\\\\\\\
[8cos^4(\theta)-8cos^2(\theta)+1]cos(\theta)\\\\
-
[4sin(\theta)cos(\theta)-8sin^3(\theta)cos(\theta)]sin(\theta)$

distribute... and simplify :)

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3 years ago

80% of how many games is 32 games

ipn [44]

About 25 games

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3 years ago