In order to change from 35 to 62, we have to add 27. So, the question becomes: which percentage of 35 is 27?
To answer this question, we set this simple equation

And solving for x we have

So, if you change from 35 to 62, you have an increase of about 77%
The answer is 6. because a hexagon has 6 sidea
Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

Hence the bounds of the interval are found as follows:


The 95% confidence interval is (0.2316, 0.3112).
More can be learned about the z-distribution at brainly.com/question/25890103
Answer:
<u>Total Cost (in dollars) = a + c</u>
Step-by-step explanation:
<u>Algebra</u>
When mathematics quantities are generalized into letters or variables, then we are dealing with algebra.
We are said the cost of an adult's ticket into a theme park is $a and a child's ticket costs $c. Since both quantities are unknown, we must treat them as variables and use the same logic procedure to solve the problem as if they were numbers.
The total cost for an adult and a child is the sum of both individual costs, thus
Total Cost (in dollars) = a + c