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Harrizon [31]
2 years ago
10

Which number is divisible by both 2 and 4? A. 1,022 B. 1,974 C. 2,836 D. 2,918

Mathematics
2 answers:
sdas [7]2 years ago
7 0

Answer:

C, 2,836

Hope this helps :)

If it did please give branliest :)

Kobotan [32]2 years ago
3 0
The correct answer is C. 2,836

when 2836 is divided by 2 it equals 1418. when it is divided by 4 it equals 709. 709 is a whole number, therefore it is correct, and can be divided by both 2 and 4.
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Solve each system by substitution.<br> 1) y = 2x + 2<br> y = -5x + 16
dalvyx [7]

Answer:

y = 6

x = 2

Step-by-step explanation:

rearrange the first equation in terms of x

x = (y - 2)/2

substiute x in the second equation

y = -5[(y-2)/2] +16

Now simpilify and solve for y

y = (-5y + 10)/2 +16

y = -5/2y + 5 + 16

y + 5/2y = 5 + 16

3.5y = 21

y = 6

Now substitue y in the first equation to solve for x

x = (6 - 2)/2

x = 2

5 0
2 years ago
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Suppose you have 20 coins that total $3.00. Some coins are nickels and some are quarters. Which of the following pairs of equati
shusha [124]

Answer: D. n + q = 20

5n + 25q = 300

Step-by-step explanation:

Let n represent the number of nickels that you have.

Let q represent the number of quarters that you have.

Suppose you have 20 coins. It means that

n + q = 20

The total value of the coins is $3. The value of a quarter is $0.25 and the value if a nickel is $0.05. Therefore, the equation would be

0.05n + 0.25q = 3

Multiplying both sides of the equation by 100, it becomes

5n + 25q = 300

The correct option is

D. n + q = 20

5n + 25q = 300

6 0
2 years ago
Use a calculator to find the
Tamiku [17]
Use the calculator to find the Product
8 0
3 years ago
Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two
In-s [12.5K]
Let the original 2-digit number be xy.
Because 5 times the sum of the digits is 13 less than the number, therefore
5(x + y) = 10x + y - 13 
5x + 5y = 10x + y - 13
-5x + 4y = - 13             (1)

The number with reversed digits is yx.
Because 4 times the sum of the digits is 21 less than the reversed 2-digit number, therefore
4(x + y) = 10y + x - 21
4x + 4y = 10y + x - 21
3x - 6y = -21
x - 2y = -7
x = 2y - 7                 (2)

Substitute (2) into (1).
-5(2y - 7) + 4y = -13
-10y + 35 + 4y = -13
-6y = -48
y = 8

From (3), obtain
x = 2*8 - 7 = 9

Answers:
The original 2-digit number is 98
The reversed 2-digit number is 89
The difference between the original and the reversed 2-digit numbers is
98 - 89 = 9
4 0
3 years ago
Divide and round to the nearest hundredths place.<br> 4.05 ÷ 0.07
Vesna [10]
57.857143 is the answer. 

5 0
3 years ago
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