To obtain these 2 points within slope intercept form, what you would need to do, is first find the slope, using the formula for slope.
M = y2-y1/x2-x1 = 3 - 2/1 - 5 = 1/-4 or -1/4.
Knowing this, choose any one of the point and put it in the form y = mx + b.
Y = mx + b
2 = -1/4(5) + b
2 = -5/4 + b
2 = b - 5/4
b = 5/4 + 2/1
b = 5/4 + 8/4 = 13/4
Y = -1/4x + 13/4.
1m=100cm
85 cm
400 mm=40 cm
Add up them up and you get 225 cm in total
Answer:p=28 and q=4(7)
Step-by-step explanation:
p=28 and q=4(7)
Answer:
The maximum value of P is 34 and the minimum value of P is 0
Step-by-step explanation:
we have the following constraints
----> constraint A
----> constraint B
----> constraint C
----> constraint D
Solve the feasible region by graphing
Using a graphing tool
The vertices of the feasible region are
(0,0),(0,5.33),(2,4),(6,0)
see the attached figure
To find out the maximum and minimum value of the objective function P, substitute the value of x and the value of y for each of the vertices in the objective function P, and then compare the results
we have
For (0,0) ---->
For (0,5.33) ---->
For (2,4) ---->
For (6,0) ---->
therefore
The maximum value of P is 34 and the minimum value of P is 0