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scoundrel [369]
4 years ago
6

Find such a coefficient a for the linear equation ax –y=4, so that the graph of the equation would pass through the point M (3,

5). Build the graph of this equation.
Mathematics
1 answer:
denis-greek [22]4 years ago
5 0
Use the point (3,5) as (x,y) to solve for the coefficient "a"

a(3) - (5) = 4

3a - 5 = 4
3a = 4+5
3a = 9
a = 3


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Which shows the correct word and expanded forms for the decimal? 3.28
liberstina [14]
The correct answer is:  [D]:
___________________________________________ 
    " three and twenty-eight hundredths ;  3 + 0.2 + 0.08 " .
___________________________________________
Note:  Given:  "3.28" .
_________________________
      3
   + 0.2
      0.08
____________
      3.28 ;
___________________________
  Note:  The whole number, "3" (three);  

            "twenty-eight hundredths" = 28/100 = 28 ÷ 100 = 0.28  ; 
___________________________________________________
          Note:  0.2 = 2/10 = 20/100 = 20÷100 = 0.20 = 0.2 ;
___________________________________________________
          Note:  0.08 = 8/100 = 8÷100 = 0.08 ;
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8 0
3 years ago
HELP ANYONE PLZZZ ?
sattari [20]

9514 1404 393

Answer:

  1. 4
  2. A. 0

Step-by-step explanation:

1. Input 3 for x and do the arithmetic.

  z(x) = x+1

  z(3) = 3+1 = 4 . . . . . the output is 4

__

2. The expression for n(x) has x in the denominator. The expression will be undefined when the denominator is zero, so x=0 cannot be used.

5 0
3 years ago
the equation x^3-3x=1 has a solution between 1.8 and 1.9. use a trial and improvement method to find this solution. give your an
Reika [66]

Answer:

The solution to the equation x³ - 3x = 1 is given as :

1.88

Step-by-step explanation:

In the above question, we are given the equation

x³ - 3x = 1 ... Equation 1

and we are told the answer lies between 1.8 - 1.9

Using the trial and improvement method approximating to 2 decimal places

a. First trial we use 1.84 for x in equation 1

1.84³ - 3×1.84 = 0.71

This first trial using 1.84 too small

b. Second trial we use 1.86 for x in equation 1

1.86³ - 3×1.86 = 0.86

This second trial using 1.86 as well is too small

c. For our third trial we use 1.89 for x in equation 1

1.89³ - 3×1.89 = 1.08

This third trial using 1.89 is large. Our target is 1.00

d. Our fourth trial we use 1.88 for x in equation 1

1.88³ - 3×1.88 = 1.004

Approximately to 2 decimal places.

We have = 1.00

Hence the solution to the equation

x³ - 3x = 1 after using the trial and improvement method is 1.88

4 0
3 years ago
PLEASE HELP im not sure what is the answer
snow_tiger [21]

what that other person saicd

3 0
3 years ago
Help looks like i forgot to read a ruler
Mandarinka [93]

Answer: 3 3/4

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
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