The paramecium has two nuclei, a big and small one. The big one operates as the director of the cell's activities, rather like a little brain. The smaller one is used for reproduction. The paramecium splits in half (fission) just as the ameba does. First the smaller nucleus splits in half and each half goes to either end of the paramecium. Then the bigger nucleus splits and the whole paramecium splits. Occasionally two paramecium exchange material and form a new paramecium. This is called conjugation.
<span>Conjugation in Paramecia occurs in the following way: </span>
<span>a). The formation of ciliary contacts. </span>
<span>b). Local loss of cilia and formation of narrow contacts between anterioventral somatic cell membranes </span>
<span>c). Formation of small cytoplasmic bridges (which allow for the exchange of molecular components only). </span>
<span>d). Their enlargement enables the cells to exchange micronuclei. </span>
<span>Bacteria exchange plasmid material and the Paramecia exchange micronuclei.
Good luck to Steve! How is it in Neptune? XD</span>
Answer:
to know whether there is starch in the leaf
Answer:
Explanation:
Given parameters:
Mass of oxygen atom = 15.994914amu
Mass of a proton = 1.00728amu
Mass of a neutron = 1.00866amu
Unknown:
Mass defect = ?
From the periodic table, the number of the elementary particles in a neutral Oxygen atom is given below:
Number of protons = 8
Number of neutrons = 8
Number of electrons = 8
Solution
The mass defect examines the difference between the actual mass of an atom and sum of masses of the nucleons.
The mass of an atom is concentrated in the nucleus which contains protons and neutrons. Electrons have little to no weight compared with the nucleons.
To calculate the mass defect, we first know the mass of the nucleons first:
1 proton has a mass of 1.00728amu
8 protons will weigh: (8 x 1.00728)amu = 8.05824amu
For the neutrons:
1 neutron has a mass of 1.00866amu
8 neutrons will weigh: (8 x 1.00866)amu = 8.06928amu
Mass of the nucleons = mass of protons + mass of neutrons
= 8.05824amu + 8.06928amu
= 16.12752amu
The mass defect = mass of the nucleons - mass of the atom
= 16.12752amu - 15.994914amu
= 0.132606amu ≅ 0.13261amu to 5 decimal places
Ok, so I wrote these out just to make it a little bit easier for you to understand what I am about to explain.
So for the first one you have two different traits that can be inherited- having freckles or having no freckles, F and f respectively. The dominant trait (or having freckles) is shown by the capital F, and is almost always expressed over the recessive trait, or the lowercase f. So, for example, if you have a genotype of Ff, the trait having freckles will show up instead of not having freckles. The only way that you could have the trait of no freckles show up is if there are two recessive alleles for having no freckles, or ff. In this case, you have two parents who are both heterozygous for the trait of having freckles, so in other words the mother has Ff and the father has Ff. Each parent passes down one allele to the offspring, so since you are breeding Ff and Ff, you should result in having the possible genotypes of FF, Ff, Ff, and ff. This means that there is a 25% chance that the offspring will be homozygous for having freckles, a 50% chance that the offspring will be heterozygous for having freckles and a 25% chance that they would be homozygous for having no freckles, or a 1:2:1 ratio.
Incomplete dominance is a little bit different that just a normal monohybrid cross. Instead of just the dominant gene showing up in a heterozygous genotype, both traits show up. So like the question says, if a homozygous red flower plant was crossed with a homozygous white flower plant, their offspring would not just be white or red, they would be pink because it is a mixture of white and red. So then if you crossed the heterozygous, or Rr plants, the result would be a 25% chance of getting a homozygous RR red plant, a 50% chance of getting a pink Rr plant, and a 25% chance of getting a white rr plant, or another 1:2:1 ratio.
Sorry for the wordy answer, but hopefully this helps you understand this a little better :)
Answer:
3.dominant alleles more frequent than recessive alleles
Explanation:
To achieve hard-Weinberg equilibrium, certain conditions must be made.
These conditions are:
1. There is noo mutation,
2. Existence of random mating,
3. There should be no natural selection
4. There is the infinite population size
5. No migration
Hence, in this case, the correct answer is option 3, which is not a condition to be made for Hard-Weinberg equilibrium