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andrezito [222]
3 years ago
13

Use the zeros of the following quadratic to find the x-value of the vertex.

Mathematics
1 answer:
jarptica [38.1K]3 years ago
3 0
Just use the following formula:
v= (\frac{-b}{2a}, f( \frac{-b}{2a}))

In this problem, b=2 and a=1

Substitute the values into the formula.

v=(-(2)/2(1), f(-(2)/2(1)))
v=(-1,f(-1))
v=(-1,(-1)²+2(-1)-8)
v=(-1,(1-2-8))
v=(-1,-9)

Therefore, the vertex is (-1,-9).

However, you only wanted the x-value which is in fact -1.

Therefore, the correct answer is "C. -1."


To use the zeroes, just solve the quadratic and find the mean of the two zeroes.

So,
m=\frac{x_{1}+x_{2} }{2}.


Hope this helps!
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A woman bought some large frames for $10 each and some small frames for $5 each add a closeout sale if she bought 20 frames for
vampirchik [111]

Answer:

The quantity of large frames is 7

The quantity of small frames is 13

Step-by-step explanation:

Given as :

The price of each large frames = $ 10

The price of each small frames = $ 5

The total number of both frames bought = 20

The price for both the frames = $ 135

Now,

Let the quantity of large frames = L

And The quantity of small frames = S

So , According to question

The total number of both frames bought = 20

Or, The quantity of large frames + the quantity of small frame = 135

Or, L + S = 20         ......A

And $ 10 L + $ 5 S = $ 135                         ................B

Or, $ 10× ( L + S ) = $ 10× 20

Or, $ 10 L + $ 10 S = $ 200

(  $ 10 L + $ 10 S ) - ( $ 10 L + $ 5 S ) = $ 200 - $ 135

Or , ( $ 10 L - $ 10 L ) + ( $ 10 S - $ 5 S ) = $ 65

Or, 0 + 5 S = 65

∴  S = \frac{65}{5}

I.e S = 13

So, The quantity of small frames = S = 13

Put the Value of S in eq A

So , L + S = 20

Or, L = 20 - S

Or, L = 20 - 13

∴   L = 7

So, The quantity of large frames = L = 7

Hence The quantity of large frames is 7

And   The quantity of small frames is 13   Answer

7 0
3 years ago
What are the coordinates of the point LaTeX: \frac{3}{4}\:3 4of the way from A to B? coordinate plane with line segment AB. Poin
egoroff_w [7]

Answer: \left(\dfrac{-7}{2},\dfrac{5}{4}\right).

Step-by-step explanation:

It is given that Point A is at (-5, -4) and point B at (-3, 3).

We need to find the coordinates of the point which is 3/4 of the way from A to B.

Let the required point be P.

AP:AB=3:4

AP:PB=AP:(AB-AP)=3:(4-1)=3:1

It means, point P divides segment AB in 3:1.

Section formula:  If a point divides a line segment in m:n, then

\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

Using section formula, we get

P=\left(\dfrac{3(-3)+1(-5)}{3+1},\dfrac{3(3)+1(-4)}{3+1}\right)

P=\left(\dfrac{-9-5}{4},\dfrac{9-4}{4}\right)

P=\left(\dfrac{-14}{4},\dfrac{5}{4}\right)

P=\left(\dfrac{-7}{2},\dfrac{5}{4}\right)

Therefore, the required point is \left(\dfrac{-7}{2},\dfrac{5}{4}\right).

6 0
3 years ago
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