Find the 6th term of a geometric sequence t3 = 444 and t7 = 7104.

2 answers:

6 0

If we divide the 7th term by the third it gives us r^4 ( common ratio to power 4).

r^4 = 7104/444 = 16

so r = 4th root of 16 = 2

So 6th term will be the 7th term / 2 = 7104 / 2 = 3552

hichkok12 [17]3 years ago

5 0

Given the value of t3 and t7, and t7 = t3 * r^4, where r represents the geometric quotient.

So 7104 = 444 * r^4 -> solve for r, you will get r = 2 or -2

So, for r = 2, t6 = t7 / r = 7104 / 2 = 3552

For r = -2, t6 = -3552

You might be interested in

PLEASE HELP!!!!!!!!!!!!!

Marianna [84]

Answer:

Step-by-step explanation:

formula for area of a triangle is base * width * 1/2

7 0

3 years ago

Question 25 the sum of three numbers is 79 . the second number is 9 less than the first. the third number is 2 times the first.

g100num [7]

I believe the numbers are 22, 13, and 44.

4 0

2 years ago

A right square pyramid with base edges of length $8\sqrt{2}$ units each and slant edges of length 10 units each is cut by a plan

seropon [69]

Answer:

32 $unit^{3}$

Step-by-step explanation:

Given:

The slant length 10 units
A right square pyramid with base edges of length 8 $\sqrt{2}$

Now we use Pythagoras to get the slant height in the middle of each triangle:

$\sqrt{10^{2 - (4\sqrt{2} ^{2} }) }$ = $\sqrt{100 - 32}$ = $\sqrt{68}$ units

One again, you can use Pythagoras again to get the perpendicular height of the entire pyramid.

$\sqrt{68-(4\sqrt{2} ^{2} )}$ = $\sqrt{68 - 32}$ = 6 units.

Because slant edges of length 10 units each is cut by a plane that is parallel to its base and 3 units above its base. So we have the other dementions of the small right square pyramid: