Find the 6th term of a geometric sequence t3 = 444 and t7 = 7104.
2 answers:
If we divide the 7th term by the third it gives us r^4 ( common ratio to power 4).
r^4 = 7104/444 = 16
so r = 4th root of 16 = 2
So 6th term will be the 7th term / 2 = 7104 / 2 = 3552
Given the value of t3 and t7, and t7 = t3 * r^4, where r represents the geometric quotient.
So 7104 = 444 * r^4 -> solve for r, you will get r = 2 or -2
So, for r = 2, t6 = t7 / r = 7104 / 2 = 3552
For r = -2, t6 = -3552
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