Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
Answer: D.) All of the above. (happy to help)
Explanation: A.)
problem solving
B.)
expertise
C.)
content
D.)
all of the above
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Answer:
Quality of service (QOS).
Explanation:
In recent computer networking, the convergence of voice, video and text data packet has been made possible. There is no need for a dedicated network for a particular type of packet.
QOS or quality of set is a service rendered to voice or audio packets in VoIP phones to enhance communication.
The email is a digital mailing system that can be used to send all three packets. It enjoys the QOS as voice packets. It is given high preference for transmission and uses the TCP protocol to transmit data reliably.