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NemiM [27]
3 years ago
5

Give the range of the function f(x) = -x 2. a.all reals b.y ≤ 0 c.y ≥ 0

Mathematics
1 answer:
Bumek [7]3 years ago
5 0

Answer:

b. y ≤ 0

Step-by-step explanation:

Do you mean f(x) = -x^2?

If so, think of f(x) = x^2. You can use any real number for x. Once you square each value of x, you can get zero or a positive real for y. f(x) can only be a non-negative number. Now look at your function: f(x) = -x^2. The values of y are the opposite of the values of y in f(x) = x^2, so the range of f(x) = -x^2 is zero and all negative reals.

Answer: b. y ≤ 0

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Answer:

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Step-by-step explanation:

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4 0
3 years ago
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krek1111 [17]

Answer:

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Step-by-step explanation:

U= π(r+h)

Where,

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r = 220/28 ÷ 22/7

= 220/28 × 7/22

= (220 * 7) / (28 * 22)

= 1540/616

= 2.5

r = 2.5

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3 years ago
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Step-by-step explanation:

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