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Talja [164]
3 years ago
12

A company makes 120 bags.

Mathematics
2 answers:
Nana76 [90]3 years ago
8 0

Answer:

43 out of 120 have zips

Step-by-step explanation:

because

Bingel [31]3 years ago
3 0

Answer:

47 bags

Step-by-step explanation:

A company makes 120 bags.

40 of the bags have buttons but no zips.

43 of the bags have zips but no buttons.

33 of the bags have neither zips nor buttons

so

120 total bags - 40 (no zips) - 33 (neither zips nor buttons) = 47

therefore

the number of bags that have zips on them is 47 bags.

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A 95% confidence is given by (15,20) . The interval is based on a sample of size n=25 .
love history [14]

Answer:

b. quadruple the sample size.

Step-by-step explanation:

Given that a 95% confidence is given by (15,20) .

this implies that mean = average of lower and higher bounds of confidence interval = \frac{15+20}{2} =17.5

Margin of error = Upper bound - Mean = 20-17.5 = 2.5

Confidence level = 95%

Critical value = 1.96

Std  error = \frac{2.5}{1.96} =1.27551

Std devition = Std error * sqrt n = 6.3775

If we want to reduce margin of error by half we must get margin of error as 1.25

For that std error for same critical value = 0.63775

Std deviation did not change

So sample size only changed which implies that sample size is 4 times the original

b. quadruple the sample size.

5 0
3 years ago
Use the method of undetermined coefficients to find the general solution to the de y′′−3y′ 2y=ex e2x e−x
djverab [1.8K]

I'll assume the ODE is

y'' - 3y' + 2y = e^x + e^{2x} + e^{-x}

Solve the homogeneous ODE,

y'' - 3y' + 2y = 0

The characteristic equation

r^2 - 3r + 2 = (r - 1) (r - 2) = 0

has roots at r=1 and r=2. Then the characteristic solution is

y = C_1 e^x + C_2 e^{2x}

For nonhomogeneous ODE (1),

y'' - 3y' + 2y = e^x

consider the ansatz particular solution

y = axe^x \implies y' = a(x+1) e^x \implies y'' = a(x+2) e^x

Substituting this into (1) gives

a(x+2) e^x - 3 a (x+1) e^x + 2ax e^x = e^x \implies a = -1

For the nonhomogeneous ODE (2),

y'' - 3y' + 2y = e^{2x}

take the ansatz

y = bxe^{2x} \implies y' = b(2x+1) e^{2x} \implies y'' = b(4x+4) e^{2x}

Substitute (2) into the ODE to get

b(4x+4) e^{2x} - 3b(2x+1)e^{2x} + 2bxe^{2x} = e^{2x} \implies b=1

Lastly, for the nonhomogeneous ODE (3)

y'' - 3y' + 2y = e^{-x}

take the ansatz

y = ce^{-x} \implies y' = -ce^{-x} \implies y'' = ce^{-x}

and solve for c.

ce^{-x} + 3ce^{-x} + 2ce^{-x} = e^{-x} \implies c = \dfrac16

Then the general solution to the ODE is

\boxed{y = C_1 e^x + C_2 e^{2x} - xe^x + xe^{2x} + \dfrac16 e^{-x}}

6 0
1 year ago
A dance academy charges $10 per class and a one-time registration fee for $50 , a student pays a total of $90 to the academy , f
swat32

Answer:4 classes

Step-by-step explanation:

3 0
3 years ago
A pizza parlor offers a choice of 16 different toppings. how may three-topping pizzas are possible
Mariulka [41]
48. 16 times 3 is 48:)

7 0
3 years ago
A cake has a circumference of 25 1/7 inches. What is the area of the cake? Use 22/7 to approximate pi
Novosadov [1.4K]
To calculate for area given the circumference we proceed as follows:
C=2πr
where:
r=radius
thus given that C=25 1/7 in=176/7
thus plugging in our formula to solve for r we get:
176/7=2πr
thus
r=4.002~4.00 in
hence the area will be:
A=πr²
A=π×(4²)
A=50 2/7 in²


7 0
4 years ago
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