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borishaifa [10]
3 years ago
9

What is the value of sin X

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
4 0

\sin(x)  =  \frac{opposit e \: cathetus}{hypotenuse}
Then sin(x) = 5/13
AURORKA [14]3 years ago
3 0
Sinx according to theorem is opposite side with length 5cm divide with hypotenuse with length 13cm

correct answer is sinx= 5/13
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Simplify (2z^5)(12z^3)/4z^4
Sphinxa [80]

Answer:

6z^{4}

Step-by-step explanation:

Given in the question an expression,

\frac{ (2z^5)(12z^3)}{4z^4}

Step 1

Apply exponential "product rule"

x^{m}x^{n}=x^{m+n}

\frac{ 12(2)z^5)(z^3)}{4z^4}

\frac{ (24)z^5)(z^3)}{4z^4}

\frac{ 24(z^{(5+3)})}{4z^4}

\frac{ 24(z^{8})}{4z^4}

Step 2

Apply exponential " divide rule"

\frac{x^{m}}{x^{n}}=x^{m-n}

\frac{24/4(z^{8})}{z^4}

\frac{6(z^{8})}{z^4}

\frac{6(z^{8-4})}{1}

6z^{4}

5 0
2 years ago
Limit definition for slope of the graph, equation of tangent line point for<br> f(x)=2x^2 at x=(-1)
Tems11 [23]

The slope of the tangent line to f at x=-1 is given by the derivative of f at that point:

f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}

Factorize the numerator:

2x^2-2=2(x^2-1)=2(x-1)(x+1)

We have x approaching -1; in particular, this means x\neq-1, so that

\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)

Then

f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4

and the tangent line's equation is

y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2

6 0
3 years ago
Need help with this question asap!!
adoni [48]
Well. it's possible that the segments are congruent but the other answer aren't as probable.
6 0
3 years ago
Consider the function f(x) = -√x . Which list contains three points that lie on the graph of the function? O (1, - 1), (4, - 2),
liq [111]
1-1-) 6,10,15, 100
1(,5,4)
5 0
3 years ago
What is the distance between (4,5) and (4,-3)?
Bas_tet [7]
8 is the distance between the two points
7 0
3 years ago
Read 2 more answers
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