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borishaifa [10]
3 years ago
9

What is the value of sin X

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
4 0

\sin(x)  =  \frac{opposit e \: cathetus}{hypotenuse}
Then sin(x) = 5/13
AURORKA [14]3 years ago
3 0
Sinx according to theorem is opposite side with length 5cm divide with hypotenuse with length 13cm

correct answer is sinx= 5/13
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The diameter of the circle above is 32 in. What is the circumference of the circle? Use = 3.14.
KonstantinChe [14]

Answer:

8.3776 this is the circumference

Step-by-step explanation:

4 0
3 years ago
A rectangle pool is 7 ft wide, it is 3 times as long as it is wide what’s the dimensions of the pool?
svetoff [14.1K]

The length is 3 times longer than the width (7)

3 x 7 = 21

the length is 21.

To find perimeter, add all sides together:

21 + 21 + 7 + 7 = 42 + 14 = 56

56 ft is your answer

hope this helps

3 0
3 years ago
Read 2 more answers
Determine the coordinator of the point<br>of intersection of lines<br>3x-2y=13 and 2y+x+1=0​
finlep [7]

Answer:

(3,-2)

Step-by-step explanation:

Given equations of line

3x-2y=13

2y+x+1=0​

=> x = -1 -2y

Point of intersection will coordinates where both equation have same value of (x,y)

top get that we have to solve the both equations by using method of substitution of simultaneous equation.

using this value of x in 3x-2y=13, we have

3(-1-2y) -2y = 13

=> -3 -6y-2y = 13

=> -8y = 13+3 = 16

=> y = 16/-8 = -2

x = -1 - 2y = -1 -2(-2) = -1+4= 3

Thus, point of intersection of line is (3,-2)

3 0
3 years ago
2/5g+3h-6 when g=10 and h=6
faust18 [17]
<span>2/5g+3h-6 when g=10 and h=6

</span><span>2/5 (10) +3(6) - 6
</span><span>= 4 + 18 - 6
= 16

</span>
4 0
3 years ago
The area of a rectangle is 66 ft2, and the length of the rectangle is 1 ft more than twice the width. Find the dimensions of the
umka21 [38]
This is probably way overcomplicated but i cant remember how to do it
w = n
l = 2n+1
w*l = 66
n(2n+1) = 66
2n^2 + n =66
2n^2 + n - 66 = 0
using quadratic equation

n = 11/2

width = 11/2 = 5.5
length = 11 + 1 = 12
3 0
3 years ago
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