A: x= 6+3 squareroot 10 ... Its letter A
Answer:
The roots of the equation 2m²+3=m are non-real roots.
Step-by-step explanation:
Given equation:
2m²+3=m
2m²-m+3=0
Here, from the equation we can obtain the following values:
a = 2, b = -1, c = 3
Discriminant of an equation is given as:
D = b²-4ac
= (-1)²-4(2)(3)
= 1 - 21
= -20
Discriminant can tell what kinds of roots the equation have.
In our case, the discriminant is less than 0.
When D < 0, the roots of the equation are complex conjugates.(non-real)
Answer:
(6.8, 1.3)
Step-by-step explanation:
<u>Given</u>:
A(-3, -5), B(11, 4)
<u>Find</u>:
P such that AP/AB = 7/10
<u>Solution</u>:
Using the desired relation, we have ...
(P -A)/(B -A) = 7/10
10(P -A) = 7(B -A) . . . . . multiply by 10(B-A)
10P = 7B +3A . . . . . . . . add 10A to both sides
10P = 7(11, 4) +3(-3, -5) = (77 -9, 28 -15) = (68, 13)
P = (68, 13)/10 = (6.8, 1.3)
The point 7/10 of the way from A to B is (6.8, 1.3).
The answer is B lm 100% sure
See attached graph: v is on the y-axis and t is on the x-axis
