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faust18 [17]
3 years ago
12

If there are a number of different sounds being produced simultaneously, the resulting intensity is the sum of the individual in

tensities. How many decibels louder is the sound of quintuplets crying than the sound of one baby crying?
Mathematics
1 answer:
podryga [215]3 years ago
8 0
Formula: Δ L = 10 × log n. 
<span>Δ L = level difference. </span>
<span>n = number of equal loud sound sources. </span>

n = 5 
10 × log10 5 = +<span>6.9897</span><span> dB compared to the case that only one source is available. </span>
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