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Inga [223]
3 years ago
8

A survey showed that 9 of every 25 students liked dogs while 13 of every 20 students liked cats. How many more of the students l

ike cats than dogs?
Mathematics
2 answers:
alexira [117]3 years ago
6 0

Answer:

\frac{29}{100}

Step-by-step explanation:

We have been given that a survey showed that 9 of every 25 students liked dogs while 13 of every 20 students liked cats.

We can represent our given information as fraction:

\frac{9}{25} and \frac{13}{20}

To solve our given problem, we will subtract fraction of students like dogs from fraction of student that like cats.

\frac{13}{20}-\frac{9}{25}

Make a common denominator:

\frac{13*5}{20*5}-\frac{9*4}{25*4}

\frac{65}{100}-\frac{36}{100}

\frac{65-36}{100}

\frac{29}{100}

Therefore, \frac{29}{100} students like cats more than dogs.

ArbitrLikvidat [17]3 years ago
3 0
<span>If the total number of students is 100, then 36 students like dogs and 65 like cats.  So 29 more students like cats than dogs. </span>
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The sum of two numbers is -14 one number is 20 less than the other find the numbers
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Answer:

x=-17,y=3

Step-by-step explanation:

x+y=-14

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3 years ago
Seven more than the product of 7 and a number
n200080 [17]
Answer:

7 + 7n

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8 0
2 years ago
Read 2 more answers
Need help again asap please! Find the sum of the first 30 terms of the sequence below an=3n+2
hoa [83]

S_{30} = 1455

generate a few terms of the sequence using a_{n} = 3n + 2

a_{1} = ( 3 × 1) + 2 = 5

a_{2} = (3 × 2) + 2 = 8

a_{3} = (3 × 3 ) + 2 = 11

a_{4} = (3 × 4 ) + 2 = 14

a_{5} = ( 3 × 5 ) + 2 = 17

the terms are 5, 8, 11, 14, 17

these are the terms of an arithmetic sequence

sum to n terms is calculated using S_{n} = \frac{n}{2} [ 2a + (n-1)d]

where a is the first term and d the common difference

d = 8 - 5 = 11 - 8 = 14 - 11 = 3 and a_{1} = 5

S_{30} = \frac{30}{2} [( 2 × 5) + (29 × 3) ]

= 15( 10 + 87) = 15 × 97 = 1455



3 0
3 years ago
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