If C is between A and B, then, we can write the equation

Substitute the value of AB and the expressions for AC and CB in terms of x.

We can now solve for x.


Dividing by 5.








Answer:
2x + y = -4
Step-by-step explanation:
standard form of equation of straight line is
ax+by = c
that is terms containing x and y should be on LHS and constant term should be on RHS
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Given equation
y + 1 = - 2x - 3
lets bring -2x on LHS ,
add 2x on lHS and RHS
y + 1 + 2x = - 2x - 3 + 2x
=> y + 1 + 2x = -3
on lHS, 1 is there which constant term lets bring it on RHS
subtract 1 from both sides
y + 1 + 2x - 1= -3 -1
y + 2x = -4
rearranging it
2x + y = -4 (Answer)
Answer:
The other zeros are -2 and 3.
Step-by-step explanation:
As 1 is a zero then (x - 1) is a factor so we divide:
x - 1 )x^3-2x^2-5x+6(x^2-x-6
x^3-x^2
-x^2-5x
-x^2+x
-6x+6
-6x+6
...........
x^2 - x - 6 = 0
(x - 3)(x + 2)
x = -2, 3.
Answer:
2y=4 is a linear function
Step-by-step explanation:
Since 2y=4 is the same as 2y¹=4, then a degree of 1 makes the function linear, aka. a straight line.