All categories

3 years ago

PLEASE HELP 10 POINTS

Mathematics

2 answers:

kifflom [539]3 years ago

6 0

we are given

$radius=r=12inches$

we have to find circumference

so, we can use formula

$C=2\pi r$

where

r is radius

C is circumference

we are given

r=12

so, we can plug here

$C=2\pi *12$

$C=24\pi$

Since, it is asking for exact circumference

it means it should be without any decimal

so,

$Circumference =24\pi inches$ ............Answer

oee [108]3 years ago

3 0

The exact radius of a circle with a radius of 12 inches is 75.4. The formula is 2πr.

You might be interested in

This morning, Mandy took a history test. There were 70 multiple-choice problems on the test and Mandy answered 70% of them corre

Anna71 [15]

I believe She got 50 correct

3 0

2 years ago

WILL MARK BRAINLIEST what is the domain of (f/g) (x)?

tatyana61 [14]

Given that $f(x) = \sqrt{7-x}$ and $g(x) = \sqrt{x + 2}$ , we can say the following:

$\Bigg(\dfrac{f}{g}\Bigg)(x) = \dfrac{f (x)}{g(x)} = \dfrac{\sqrt{7 - x}}{\sqrt{x+2}}$

Now, remember what happens if we have a negative square root: it becomes an imaginary number. We don't want this, so we want to make sure whatever is under a square root is greater than 0 (given we are talking about real numbers only).

Thus, let's set what is under both square roots to be greater than 0:

$\sqrt{7 - x} \Rightarrow 7 - x \geq 0 \Rightarrow x \leq 7$

$\sqrt{x + 2} \Rightarrow x + 2 \geq 0 \Rightarrow x \geq -2$

Since both of the square roots are in the same function, we want to take the union of the domains of the individual square roots to find the domain of the overall function.

$x \leq 7 \,\,\cup x \geq -2 = \boxed{-2 \leq x \leq 7}$

Now, let's look back at the function entirely, which is:

$\Bigg( \dfrac{f}{g} \Bigg)(x) = \dfrac{\sqrt{7 - x}}{\sqrt{x+2}}$

Since $\sqrt{x + 2}$ is on the bottom of the fraction, we must say that $\sqrt{x + 2} \neq 0$ , since the denominator can't equal 0. Thus, we must exclude $\sqrt{x + 2} = 0 \Rightarrow x + 2 = 0 \Rightarrow x = -2$ from the domain.