Answer:
A racer has just completed his first lap at a speed of 198m/s. Now his speed decrease or he decelerateted at 195m/s after 2s of his completion of first lap, as soon as he saw a curve path(line segment R). He then moved at a constant speed of 195m/s for the next 2s(line segment s). Then the race track after 4s of the completion of first lap was straight, so the racer accelerated to 200m/s within 2s( line segment T) and traveled at a constant speed for the next 6s( line segment U). After 12s from the first lap completion, he immediately saw a curve track, so he decelerateted to the speed of 194m/s within 3s( line segment V).
Hope it helped.
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<h3>
Answer: Choice B</h3>
No, this is not a plausible value for the population mean, because 5 is not within the 95% confidence interval.
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Explanation:
The greek letter mu is the population mean. It has the symbol 
which looks like the letter 'u' but with a tail at the front or left side.
The question is asking if mu = 5 is plausible if the researcher found the 95% confidence interval to be 5.2 < mu < 7.8
We see that 5 is <u>not</u> in that interval. It's a bit to the left of 5.2
Since mu = 5 is not in the interval, it's not a plausible value for the population mean.
Have we ruled it out with 100% confidence? No. Such a thing is not possible. There's always room for (slight) error. The researcher would need to do a census to be fully confident; however, such practices are very time consuming and expensive. This is the main reason why statistics is important to try to estimate the population with a sample.
Answer:
Yes, the statement is true
Btw, it's an angle not angel
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Answer:
3
Step-by-step explanation:
d=√8-5 = √9 = 3
Answer:
(a) y(x)=53+7x
(b) 179
Step-by-step explanation:
Since the first row has 60 seats and next row has 7 additional seats then we can represent it as
First row=60
Second row=60+7=67
Third row=67+7=74
The difference is always 7. If you deduct 7 from dirst row we get 60-7=53 seats
To get rhe number of seats in any row x then let y be the number of seats in row x
y=53+7(x)
For raw 1
Y=53+7(1)=60
For raw 2
Y=53+7(2)=67
Therefore, the formula for number of seats at any row will be
y(x)=53+7(x)
(b)
Using the above formula
y(x)=53+7(x)
Replace x with 18 hence
Y(18)=53+7*(18)=179 seats
