The range of the given relation is D. R = {-1, 3, 5, 8}.
Step-by-step explanation:
Step 1:
The range of a relation is the second set of values while the domain constitutes the first set of values.
There are 4 given relations with two sets of values so there would be 4 domain values and 4 range values.
Step 2:
The range of (1, -1) = -1,
The range of (2, 3) = 3,
The range of (3, 5) = 5,
The range of (4, 8) = 8.
Combining these values we get the range as {-1, 3, 5, 8} which is option D.
It has one solution that I know of
Answer:
vertex is (4,-4) and another point is (6,0) or you could use (2,0) or many other options :)
Step-by-step explanation:
The cool thing about this question your quadratic is in factored form so your x-intercepts are easy to figure out, they are 2 and 6.
So you can plot (6,0) and (2,0).
The vertex will lie half between x=2 and x=6... so it lays at (6+2)/2=4
We just have to find the y-coordinate for when x=4.
Plug in 4 gives you (4-2)(4-6)=(2)(-2)=-4.
So the vertex is at (4,-4).
The area of a parallelogram is:
A = b * h
Where,
b: base
h: height
Clearing the base we have:
b = A / h
Substituting values we have:
b = (6x2 + x + 3) / 3x
Rewriting we have:
b = 2x + 1 / x + 1/3
Answer:
the length of the base is:
b = 2x + 1 / x + 1/3
Answer:
D. ![xy\sqrt[3]{9y}](https://tex.z-dn.net/?f=xy%5Csqrt%5B3%5D%7B9y%7D)
Step-by-step explanation:
![\sqrt[3]{9x^3y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9x%5E3y%5E4%7D)
![\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7D%5Csqrt%5B3%5D%7Bx%5E3%7D%5Csqrt%5B3%5D%7By%5E4%7D)
The ![\sqrt[3]{x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D)
cancels out to become x:
![\sqrt[3]{9}x\sqrt[3]{y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7Dx%5Csqrt%5B3%5D%7By%5E4%7D)
Split the 
![\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7Dx%5Csqrt%5B3%5D%7By%5E3%7D%5Csqrt%5B3%5D%7By%5E1%7D)
![\sqrt[3]{y^3} =y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E3%7D%20%3Dy)
![xy\sqrt[3]{9} \sqrt[3]{y}](https://tex.z-dn.net/?f=xy%5Csqrt%5B3%5D%7B9%7D%20%5Csqrt%5B3%5D%7By%7D)
Put the cube root of y and cube root of 9 together:
