Geometry help!! #48 plz show work

Mathematics

1 answer:

kkurt [141]3 years ago

3 0

A ladder placed against a wall will form a triangle with the wall and the ground. Using geometric ratios you can calculate the missing values. If you have an angle of 75.5 degrees and a hypotenuse/diagonal of 10, you need to calculate the height. Use sine.

Sine=opposite/hypotenuse

Sin75.5=0.97

0.97=opposite/10

10 x 0.97 = 9.7

The maximum height that the ladder can reach is 9.7 meters

You might be interested in

10 < 0.25 ( x + 1 ) < 11

AURORKA [14]

10 <0.25 (x + 1) <11
We must solve two inequalities in this case.
Inequality 1:
10 <0.25 (x + 1)
10 / 0.25 <x + 1
40 <x + 1
40-1 <x
39 <x
Inequality 2:
0.25 (x + 1) <11
(x + 1) <11 / 0.25
(x + 1) <44
x <44-1
x <43
The final result is:
39 <x <43
Answer:
39 <x <43

6 0

3 years ago

The graph shown is for the inequality y ≥ x. The graph has one thing wrong. What is it?

Reika [66]

Flip the x and y like in the coordinate plane x,y not y,x

5 0

3 years ago

A ball is dropped from a height of 192 inches onto a level floor. After the third bounce it is still 3 inches off the ground. Pr

ANEK [815]

Answer: The required fraction = $\dfrac18$

Step-by-step explanation:

Let the required fraction = $\dfrac{p}{q}$

Given: Initial height = 192 inches

Height of ball after second bounce = $\dfrac{p}{q}\times192$

Height of ball after third bounce = $\dfrac{p}{q}\times\dfrac{p}{q}\times192=192\dfrac{p^2}{q^2}$

After the third bounce it is 3 inches off the ground.

So,

$(\dfrac{p}{q})^2192=3\\\\\\(\dfrac{p}{q})^2=\dfrac{3}{192}\\\\(\dfrac{p}{q})^2=\dfrac{1}{64}\\\\(\dfrac{p}{q})^2=(\dfrac{1}{8})^2\\\\ \dfrac{p}{q}=\dfrac{1}{8}$