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earnstyle [38]
2 years ago
6

What type of system is the following set of equations?

Mathematics
1 answer:
iVinArrow [24]2 years ago
7 0
-3x+y=-2 \\
y-4=-6x \ \ \ |\times (-1) \\ \\
-3x+y=-2 \\
\underline{-y+4=6x} \\
-3x+y-y+4=6x-2 \\
-3x+4=6x-2 \\
-3x-6x=-2-4 \\
-9x=-6 \\
x=\frac{-6}{-9} \\
x=\frac{2}{3} \\ \\
y-4=-6 \times \frac{2}{3} \\
y-4=-4 \\
y=-4+4 \\
y=0 \\ \\
(x,y)=(\frac{2}{3},0)

The system has one solution so it's A. consistent and independent.
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8 + x = 25 \\ x = 25 - 8 \\ 17

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Percent sales tax: 7%<br> price before tax: $250<br> price with tax:
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"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen
Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }]

Where

p' is the sample proportion/point estimator of the population proportion

Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} } is the margin of error (d) of the confidence interval.

Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648

So

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }

(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}

n*(d*Z_{1-\alpha /2})^2= p'(1-p')

n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}

n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0
3 years ago
Solve for y: 5x-3y&lt;75
Arada [10]

y<-5/3x+25 Is your answer. To get it you subtract the 5x to both sides and then you divide the 3 on both sides



answer : y < -5/3x +25


4 0
3 years ago
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