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Radda [10]
3 years ago
11

What is the relationship between angle BAC and angle BOC?

Mathematics
1 answer:
Basile [38]3 years ago
3 0

In this problem, an angle like angle BAC where the vertices like on the circle itself is called the inscribed angle.

While angle BOC, where O is the center of the circle, is called the central angle.

Using  Proposition III.20 from Euclid's Elements, this is called the Inscribed Angle Theorem  wherein:

∠BOC = 2∠BAC

or ∠BOC / 2 = ∠<span>BAC</span>

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Diane received 300 votes in the election for student council president. That was 60% of the students who voted election. How man
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Answer:

  500

Step-by-step explanation:

The problem statement tells you ...

  300 = 0.60×voters

Dividing by the coefficient of the variable gives ...

  300/0.60 = voters = 500

500 students voted in the election.

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Please answer the question from the attachment.
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we believe that 42% of freshmen do not visit their counselors regularly. For this year, you would like to obtain a new sample to
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Answer:

A sample of 1077 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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The margin of error is of:

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This means that \pi = 0.42

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

How large of a sample size is required?

A sample size of n is required, and n is found when M = 0.035. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.035 = 2.327\sqrt{\frac{0.42*0.58}{n}}

0.035\sqrt{n} = 2.327\sqrt{0.42*0.58}

\sqrt{n} = \frac{2.327\sqrt{0.42*0.58}}{0.035}

(\sqrt{n})^2 = (\frac{2.327\sqrt{0.42*0.58}}{0.035})^2

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A sample of 1077 is required.

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no

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