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Kruka [31]
3 years ago
8

What is 5c^4-3125 factored completely?

Mathematics
2 answers:
vovikov84 [41]3 years ago
7 0
Factor 3125 -> 5^5
5c^4-3125
=5c^4-5^5
=5(c^4-5^4)
=5(c^2+5^2)(c^2-5^2)
=5(c^2+5^2)(c+5)(c-5)
Allushta [10]3 years ago
4 0
Factor 3125 -> 5^5
so
5c^4-3125
=5c^4-5^5
=5(c^4-5^4)
=5(c^2+5^2)(c^2-5^2)
=5(c^2+5^2)(c+5)(c-5)
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To find both f(8) and f(-5), we will need to plug in their values for x and solve for each. Then, we can subtract them to find the final answer.

Finding f(8):

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Subtracting f(8) and f(-5):

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