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rewona [7]
3 years ago
12

The two spheres above have the same center. One has a radius of 4 cm, and the other has a radius of 5 cm. Approximately how much

space is in between the two spheres?
Mathematics
1 answer:
Zanzabum3 years ago
5 0
The space between the two spheres will be the volume of the larger sphere minus the volume of the smaller sphere.  Given that the volume of any sphere is:

V=(4πr^3)/3  The space between to sphere of different radius and positioned about the same center is:

S=(4πR^3)/3-(4πr^3)/3  I used S=volume of space, R=larger radius and r=smaller radius...

S=(4π/3)(R^3-r^3), we are told that R=5 and r=4 so

S=(4π/3)(5^3-4^3)

S=(4π/3)(125-64)

S=(4π/3)(61)

S=244π/61

S=4π cm^3

S≈12.57 cm^3  (to nearest hundredth of a ml)
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The correct answer is add the bases multiply height and divide by two
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1 year ago
Use the method of completing the square to transform the quadratic equation into the equation form (x – p)2 = q. x2 - 12x - 9 =
marissa [1.9K]

Hence, the correct answer is: C) (x - 6)^2 = 45

Further explanation:

Given equation is:

x^2-12x-9=0

We will move the constant term on other side of the equation

x^2-12x=9

To complete the square, we will take the coefficient of x and divide it by 2, as we already know that one term is x.

\frac{12}{2}=6

So, adding (6)^2 on both sides

(x)^2-2.x.6+(6)^2=9+(6)^2\\(x-6)^2=9+36\\(x-6)^2=45

Hence, the correct answer is: C) (x - 6)^2 = 45

Keywords: Quadratic Equation, Solution of equation

Learn more about quadratic equation at:

  • brainly.com/question/4695279
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7 0
3 years ago
Calculate the force acting on a body of mass 0.8kg (g=9.8*-2; F=mg)
bazaltina [42]

The force acting on a body of mass 0.8 kg is F = 7.84 kg-m-s⁻² or F = 7.84 N

<h3>What is mass?</h3>

A tangible body's mass is the amount of matter it possesses. It's also a metric of inertial or the resistance to velocity when a net force is exerted.

We have:

The mass of the body m = 0.8 kg

As we know,

F = mg

F is the force acting on the body and g is the acceleration due to gravity.

g = 9.8 m-s⁻²

F = (0.8)(9.8)

F = 7.84 kg-m-s⁻²

or

F = 7.84 N

Thus, the force acting on a body of mass 0.8 kg is F = 7.84 kg-m-s⁻² or F = 7.84 N

Learn more about the mass here:

brainly.com/question/15959704

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8 0
2 years ago
HELPP PLEASEE THANK YOU
Shtirlitz [24]
Terry would spend $11.7





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Can u change order of operations ?
Anni [7]

Answer:

its best no to

Step-by-step explanation:

The only thing you can really change is switching subtraction and addiction, or division and multiplication. In the long run though its best just to say with the regural order and its earier later on.

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