X^2-8x+16=1\\ \\x^2-8x+16-1=0\\ \\x^2-8x+15=0\\ \\\Delta = b^{2}-4ac = (-8)^{2}-4*1*15=64-60=4 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{8- \sqrt{4}}{2}=\frac{8-2}{2}= \frac{6}{2}=3\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{8+ \sqrt{4}}{2}=\frac{8+2}{2}= \frac{10}{2}=5\\ \\Answer : x=3 \ \ or \ \ x = 5
Check the picture below.
so the focus point is at 5, -1 and the directrix is above it, meaning is a vertical parabola, and is opening downwards, like in the picture.
keep in mind that the vertex is half-way between those two fellows, at a "p" distance from either, in this case 1 unit, since the parabola is opening downwards, "p" is negative then, or -1, and the vertex will be from 5, -1 up one unit, so 5,0.
Answer:
f(-2) = -6
Step-by-step explanation:
In the expression, to get f(-2);
we simply substitute the value of x with -2
We have this as;
f(-2) = -4(-2)^2 + 10
f(-2) = -4(4) + 10
f(-2) = -16 + 10
f(-2) = -6
Answer:
The answer will be 0.25 or 1/4
Step-by-step explanation:
8^(-2/3)= 0.25
HOPE THIS HELPS!! PLEASE GIVE BRAINIEST!!