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Semenov [28]
3 years ago
8

If f(x)=-4x^2+15,then f(-3)=??

Mathematics
2 answers:
katovenus [111]3 years ago
8 0
Hey there!!

Okay so here are the steps to solving this....

f(x) = -4x² + 15
f(-3) = -4(-3)² + 25
f(-3) = -4(9) + 25
f(-3) = -36 + 25
<u>f(-3) = -11</u><u />    <-------- There is your answer!<u>
</u>

I hope this helps! ^__^
Rzqust [24]3 years ago
3 0
F(-3) = -4(-3)^2 + 15

f(-3) = -4(9) +15
f(-3) = -36 +15
f(-3) =  -11
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if f(x)=2^x -10 and the domain of f(x) is the set of integers from -1 to 3, which values are elements of the range of f (x)? Sel
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The domain of the function is the range of values of x that can be used to be replaced in the equation for it to become true. We are given that the value of f(x) should range only from -1 to 3. We evaluate each of the choices and see if the values of f(x) will fall within the range.

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SOVA2 [1]

Answer:

The answer to your question is: third option, it's a parabola

Step-by-step explanation:

f(x) = (x + 4)²

f(x) = x² + 4

f(x) = (x - 4)²    I think this is the right answer, because when get the vertex, the signs are changed, if the -4 is negative, it means that the graph must be located in +4.

f(x) = x² - 4

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3 years ago
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<h3>Answer:</h3>

10

<h3>Step-by-step explanation:</h3>

2|x -4| +6 \text{ for } x = 2 \\ 2|2 -4| +6 \\ 2|-2| +6 \\ 2(2) +6 \\ 4 +6 \\ 10

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