The equation of motion of a block with mass m = 8 kg. attached to a spring whose spring Constant is k = 2 and which starts from

Question

Sever21 [200]

3 years ago

12

The equation of motion of a block with mass m = 8 kg. attached to a spring whose spring Constant is k = 2 and which starts from

rest at a point 3 cm above equilibrium is 8x ′′ + 2x = 0; x(0) = 3, x ′ (0) = 0.A. True.B. False.

Mathematics

1 answer:

Annette [7] · Answer 1 · 2022-02-11T14:41:14+03:00

Answer:

FALSE

Step-by-step explanation:

In order to be consistent with the system of unit we should decide if we are going to work with the CGS system <em>(centimeter-gram-second)</em> or the MKS system <em>(meter-kilogram-second). </em>

If we decide to work with the CGS system, the equation of motion would be

8,000x ′′ + 2x = 0; x(0) = 3, x ′ (0) = 0

since 1 Kg = 1,000 g

If we decide to work with the MKS system, the equation of motion would be

8x ′′ + 2x = 0; x(0) = 0.03, x ′ (0) = 0

given that 1 mt = 100 cm