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Sever21 [200]
3 years ago
12

The equation of motion of a block with mass m = 8 kg. attached to a spring whose spring Constant is k = 2 and which starts from

rest at a point 3 cm above equilibrium is 8x ′′ + 2x = 0; x(0) = 3, x ′ (0) = 0.A. True.B. False.
Mathematics
1 answer:
Annette [7]3 years ago
5 0

Answer:

FALSE

Step-by-step explanation:

In order to be consistent with the system of unit we should decide if we are going to work with the CGS system <em>(centimeter-gram-second)</em> or the MKS system <em>(meter-kilogram-second). </em>

If we decide to work with the CGS system, the equation of motion would be

8,000x ′′ + 2x = 0; x(0) = 3, x ′ (0) = 0

since 1 Kg = 1,000 g

If we decide to work with the MKS system, the equation of motion would be

8x ′′ + 2x = 0; x(0) = 0.03, x ′ (0) = 0

given that 1 mt = 100 cm

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