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Vesnalui [34]
4 years ago
13

Construction workers are installing a rectangular, in-ground pool. To start, they dig a rectangular hole in the ground where the

pool will be. The area of the ground that they will be digging up is 252 square feet. The length of the pool is twice the width of the pool. What are the dimensions of the pool? Round to the nearest tenth
Mathematics
1 answer:
Sever21 [200]4 years ago
8 0
Length (L) = 2 · W
Width (W) = W
Area (A) = L · W
       252 = (2W)(W)
       252 = 2W²
       126 = W²
       11.2 ≈ W
L = 2 · W
   = 2 · 11.2
   = 22.4

Dimensions: 11.2 ft x 22.4 ft

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At a sale this week, a desk is being sold for $336. This is a 36% discount from the original price.
8090 [49]

Answer:

$525

Step-by-step explanation:

We can find the original price by using the formula x - 0.36x = 336, where x is the original price, 0.36 is the discount percentage (converted to decimal form), and 336 is the total amount paid after the discount is applied:

x-0.36x=336\\0.64x=336\\x=525

To check and further understand why the formula works, we can simply apply the discount to the original price and subtract the number from the original price:

525 * 0.36 = 189

525 - 189 = 336

Modeling the first formula gives us:

525 - (0.36 * 525) = 336

525 - 189 = 336

6 0
2 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3


has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
Read 2 more answers
5x +1 = -3+10x how do you solve this
Natali5045456 [20]

Answer:

x = 4/5

Step-by-step explanation:

Group like terms together.  Start by subtracting 1 from both sides, obtaining

5x = -4 + 10x.

Then combine the x terms, obtaining 4 = 5x.

Solving for x by dividing both sides by 5, we get x = 4/5.

7 0
4 years ago
Read 2 more answers
Is 2/3 greater then1/5
Greeley [361]
Yes, it is. To find this out, you need to make the denominators the same. They can both multiply into 15, so we change the denominators to 15. Whatever we do to the bottom, we also have to do to the top.

2/3 = 10/15

1/5 = 3/15

We can then see that 10 is more than 3 :)
8 0
4 years ago
Round 7.2242 to the nearest hundredth
alukav5142 [94]
7.22 is 7.2242 rounded to the neartest hundreth

8 0
3 years ago
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