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Oksi-84 [34.3K]
3 years ago
7

Can someone help me? Kendall owns 39 CD’S, and he buys a new one every week. Raymond only owns 15 CD’S but he buys 3 new ones ea

ch week. How many weeks will it be before Raymond owns as many CD’S as Kendall?
Mathematics
1 answer:
yKpoI14uk [10]3 years ago
4 0

Answer:

  • 7 weeks

Step-by-step explanation:

Let the number of weeks be x

<u>Then Kendal's CD's</u>

  • 39 + x

<u>Raymond's CD's</u>

  • 15 + 3x

<u>Time when they have equal CD's</u>

  • 39 + x = 15 + 3x
  • 3x - x = 39 - 15
  • 2x = 14
  • x = 7 weeks
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The simplified expression of (x^0 y^2/3 z^-2y^)^2/3 divided by (x^2 z^1/2)^-6 is x^(12) y^(10/9) z^(-1/3)

<h3>How to simplify the expression?</h3>

The algebraic statement is given as:

(x^0 y^2/3 z^-2y^)^2/3 divided by (x^2 z^1/2)^-6

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[(x^0 y^2/3 z^-2y)^2/3]/[(x^2 z^1/2)^-6]

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[(x^0 y^(2/3+1) z^-2)^2/3]/[(x^2 z^1/2)^-6]

Evaluate the sum

[(x^0 y^5/3 z^-2)^2/3]/[(x^2 z^1/2)^-6]

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Apply the quotient law of indices

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Read more about simplified expression at:

brainly.com/question/723406

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