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nikklg [1K]
3 years ago
13

Which rational expression has a value of 0 when x = 2 ? A) 7x -5/x2 + 10 B) -3x +6/8x-9 C) -5x + 8 / x-2

Mathematics
2 answers:
shepuryov [24]3 years ago
7 0

answer for this question is (b) - 3 x + 6 x /8x- 9

nekit [7.7K]3 years ago
3 0
<h2>Answer:</h2>

Option: B is the correct answer.

B)     \dfrac{-3x+6}{8x-9}

<h2>Step-by-step explanation:</h2>

We are asked to find the expression which gives the value zero when we substitute x=2.

Hence, we will check each of the options by putting x=2.

A)

\dfrac{7x-5}{x^2}

when x=2 we have:

\dfrac{7\times 2-5}{2^2}\\\\=\dfrac{14-5}{4}\\\\=\dfrac{9}{4}\neq 0

Hence, option: A is incorrect.

B)

\dfrac{-3x+6}{8x-9}

when x=2 we  have:

=\dfrac{-3\times 2+6}{8\times 2-9}\\\\=\dfrac{-6+6}{16-9}\\\\=\dfrac{0}{7}\\\\=0

Hence, option: B is correct.

C)

\dfrac{-5x+8}{x-2}

when we substitute x=2

we observe that the denominator is zero but the numerator is non-zero.

Hence, x=2 is a excluded point of the rational expression.

Hence, option: C is incorrect.

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12.9 = x + 7.1
subtract 7.1 from both sides to isolate the variable, x.

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3 years ago
Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)
Lisa [10]

Answer:

f(x) = 4x^2 - 3x + 6

Step-by-step explanation:

Quadratic function is given as f(x) = ax^2 + bx + c

Let's find a, b and c:

Substituting (0, 6):

6 = a(0)^2 + b(0) + c

6 = 0 + 0 + c

c = 6

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

f(x) = ax^2 + bx + c

16 = a(2)^2 + b(2) + 6

16 = 4a + 2b + 6

16 - 6 = 4a + 2b + 6 - 6

10 = 4a + 2b

10 = 2(2a + b)

\frac{10}{2} = \frac{2(2a + b)}{2}

5 = 2a + b

2a + b = 5 => (Equation 1)

Substituting (3, 33), and c = 6

f(x) = ax^2 + bx + x

33 = a(3)^2 + b(3) + 6

33 = 9a + 3b + 6

33 - 6 = 9a + 3b + 6 - 6

27 = 9a + 3b

27 = 3(3a + b)

\frac{27}{3} = \frac{3(3a + b)}{3}

9 = 3a + b

3a + b = 9 => (Equation 2)

Subtract equation 1 from equation 2 to solve simultaneously for a and b.

3a + b = 9

2a + b = 5

a = 4

Replace a with 4 in equation 2.

2a + b = 5

2(4) + b = 5

8 + b = 5

8 + b - 8 = 5 - 8

b = -3

The quadratic function that represents the given 3 points would be as follows:

f(x) = ax^2 + bx + c

f(x) = (4)x^2 + (-3)x + 6

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3 years ago
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gulaghasi [49]

Answer:

- (x - 3y)(3x + y)

Step-by-step explanation:

Given

(x + 2y)² - (2x - y)² ← expand both parenthesis using FOIL

= x² + 4xy + 4y² - (4x² - 4xy + y²) ← distribute

= x² + 4xy + 4y² - 4x² + 4xy - y² ← collect like terms

= - 3x² + 8xy + 3y² ← factor out - 1 from each term

= - 1(3x² - 8xy - 3y²) ← factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the coefficient of the y² term which sum to give the coefficient of the xy- term.

product = 3 × - 3 = - 9 and sum = - 8

The factors are - 9 and + 1

Use these factors to split the xy- term

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= 3x(x - 3y) + y(x - 3y) ← factor out (x - 3y) from each term

= (x - 3y)(3x + y)

Thus

(x + 2y)² - (2x - y)² = - (x - 3y)(3x + y)

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Answer:

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Step-by-step explanation:

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h is the height of the cylinder

In this problem we have:

h = 96 mm is the height of the can

d = 66 mm is the diameter of the can

So the radius of its base is

r=\frac{d}{2}=\frac{66}{2}=33 mm

And therefore, the volume of the can is:

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