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artcher [175]
3 years ago
10

how many triangles are formed by the diagonal from one vertex in quadrilateral, hexagon, octagon, and decagon??! ...?

Mathematics
1 answer:
Dmitrij [34]3 years ago
3 0
The following are the details given for your answer

two for quadrilateral
six for hexagon
 eight for octagon
 and ten for decagon. <span>
</span>
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Jose can assemble 12 car parts in 40 minutes. How many minutes
Tpy6a [65]

Answer:

12/40=0.3

0.3 car parts per minute

9 / 0.3 = 30 minutes

30 minutes for 9 parts

Hope this helps

Step-by-step explanation:

8 0
3 years ago
what do the following two equations represent? please help 4x+2y= 10 4x-2y= -10 a) the same line b) distance parallel lines c) p
Lady bird [3.3K]

Answer:

D

Step-by-step explanation:

The equations are

● 4x + 2y = 10 (1)

● 4x - 2y = -10 (2)

● 4x + 2y = 10

Add - 4x to both sides

● 4x + 2y -4x = 10 -4x

● 2y = 10 -4x

Divide both sides by 2

● 2y/2 = (10 - 4x)/2

● y = 5 - 2x

● y = -2x + 5 (1)

● 4x - 2y = -10

Add -4x to both sides

● 4x -2y -4x = -10 - 4x

● -2y = -10 - 4x

Divide both sides by -2

● -2y/-2 = (-10 -4x)/-2

● y = 10 + 2x

● y = 2x + 5 (2)

So the equation are

● y = 2x + 5

● y = -2x + 5

Graph them

The lines intersect at (0,5) but aren't perpendicular

So the answer is d

8 0
3 years ago
mia has $950 in a savings account that earns 2% annual simple interest. How much money will be in her account if she does not ma
AleksAgata [21]

keeping in mind that there are 12 months in a year, thus 18 months is really 18/12 years.

\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad  \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to& \$950\\ r=rate\to 2\%\to \frac{2}{100}\to &0.02\\ t=years\to \frac{18}{12}\to &\frac{3}{2} \end{cases} \\\\\\ A=950\left(1+0.02\cdot \frac{3}{2}  \right)\implies A=950(1.03)\implies A=978.5

8 0
4 years ago
Read 2 more answers
The trapezoid has an area of 15 square feet. If the bases the are 4 feet and 6 feet, what is the height of the trapezoid?
Paladinen [302]

Answer:3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the equation of a line with a slope of 13/2<br> that passes through the point (−2, — 10).
Darya [45]

Answer:  y=\frac{13}{2} x+3

Step-by-step explanation:

Remember the point-slope equation which is y-y_{1} = m(x-x_{1} )  where(x_{1} , y_{1} ) is your <u>point</u> and m is your <u>slope.</u>

<u />

Given that we substitute what you have:

y-(-10) =\frac{13}{2} (x - (-2))

Minus and minus give us positive:

y+10 =\frac{13}{2} (x +2)

Multiply slope into the parenthesis:

y+10= \frac{13}{2}x + \frac{13}{2}*2\\

Calculate it:

y+10= \frac{13}{2}x +13

Isolate the y by subtracting 10 from both sides:

y=\frac{13}{2} x + 13 -10

Your final equation is:

y=\frac{13}{2} x +3

Hope this makes sense!

And here's the graph to prove that the line actually goes through the point (-2,-10):

3 0
2 years ago
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