Question

The figure below shows the net of a triangular pyramid. The given height is rounded to the nearest hundredth. If all the triangles are equilateral, what is the surface area of the pyramid in square centimeters? HEIGHT: 4.33 cm BASE: 5 cm. *The net shows 4 triangles but I think one of them is the base of the triangle.*

Answer 1

Answer: 43.3 square inches

Step-by-step explanation:

Formula for Triangle: A = bh/2

Key:

* = multiple

/ = divide

Fill in the formula with what you know:

A = bh/2

A = 5 * 4.33 / 2

A= 21.65 / 2 = 10.825 square inches

However, 10.825 is not our answer. 10.825 is the area of only one triangle. Since all four of the triangles are congruent (or the same) we can:

Add: 10.825 + 10.825 + 10.825 + 10.825 = 43.3 square inches

OR

Multiple: 10.825 * 4 = 43.3 square inches

Thus, the surface area of the pyramid is 43.3 square inches.