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3 years ago

Large college classes are called

1 answer:

6 0

A lecture hall is a large room used for instruction in college or university. The capacity of lecture halls are typically measured in the hundreds

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Prompt: A shared sense of shame is important for keeping society healthy.

uysha [10]

Ok here is the project sorry I didn’t want to type it all out so here is the picture of the work hope it helps

5 0

2 years ago

Read 2 more answers

Explain in detail, how you solved the following problem: The first two terms of a sequence are 10 and 20. If each term after the

KIM [24]

Answer:

$T_{2020} = 15$

Explanation:

Given

$T_1 = 10$

$T_2 = 20$

Each term after the second term is the average of all of the preceding terms

Required:

Explain how to solve the 2020th term

Solve the 2020th term

Solving the 2020th term of a sequence using conventional method may be a little bit difficult but in questions like this, it's not.

The very first thing to do is to solve for the third term;

The value of the third term is the value of every other term after the second term of the sequence; So, what I'll do is that I'll assign the value of the third term to the 2020th term

This is proved as follows;

From the question, we have that "..... each term after the second term is the average of all of the preceding terms", in other words the MEAN

$T_{n} = \frac{\sum T{k}}{n-1} ; where: k = 1 .... n -1$

Assume n = 3

$T_{3} = \frac{T_1 + T_2}{2}$

Multiply both sides by 2

$2 * T_{3} = \frac{T_1 + T_2}{2} * 2$

$2T_{3} = T_1 + T_2$

Assume n = 4

$T_{4} = \frac{T_1 + T_2 + T_3}{3}$

$T_{4} = \frac{(T_1 + T_2) + T_3}{3}$

Substitute $2T_{3} = T_1 + T_2$

$T_{4} = \frac{2T_3 + T_3}{3}$

$T_{4} = \frac{3T_3}{3}$

$T_{4} = T_3$

Assume n = 5

$T_{5} = \frac{T_1 + T_2 + T_3 +T_4}{4}$

$T_{5} = \frac{(T_1 + T_2) + T_3 +(T_4)}{4}$

Substitute $2T_{3} = T_1 + T_2$ and $T_{4} = T_3$

$T_{5} = \frac{2T_3 + T_3 +T_3}{4}$

$T_{5} = \frac{4T_3}{4}$

$T_{5} = \frac{(5-1)T_3}{5-1}$

Replace 5 with n

$T_{n} = \frac{(n-1)T_3}{n-1}$

(n-1) will definitely cancel out (n-1); So, we're left with

$T_{n} = T_3$

Hence,

$T_{2020} = T_3$

Calculating $T_3$

$T_{3} = \frac{10 + 20}{2}$

$T_{3} = \frac{30}{2}$

$T_{3} = 15$

Recall that $T_{2020} = T_3$

$T_{2020} = 15$

3 0

3 years ago

In which situation has the precautionary principle been most strictly applied? (3 points)

Cloud [144]

Answer: The last option.

Explanation: The precautionary principle would be considered to be most strictly applied where the precautionary measure is most disproportionate to the given risk. In all but the last option, there are either measures taken in response to concrete problems, or the precautionary measures are actually relaxed. In the last option, though, there are merely “fears” that antibiotics and growth hormones could cause harm (no experimental evidence), but the school board still takes the strict precautionary measure of mandating that schools only serve organic milk.

8 0

1 year ago

An influential famous hip-hop artist uses his music to express political and social issues. This is an example of

KiRa [710]

thanks for your question and please correct me if I'm wrong.

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