<span>The answer to the question is 0 percent. In order to have wrinkled seeds, the offspring must inherit two recessive alleles from the parents. From the cross of RRYY and RrYy, there is no way for the offspring to have wrinkled seeds as one of the parents doesn't have the recessive gene for it, the RRYY parent. Because of this there is 0 percent probability of having an offspring that has wrinkled seeds and yellow seed color.</span>
Answer:
B - In real world conditions
Makes the most sense.....
In order to solve this problem we use these formula:
<span>p2 + 2pq + q2 = 1p + q = 1p = % dominant allele in the population
q = % recessive allele in the population
p2 = % homozygous dominant individuals
q2 = % homozygous recessive individuals
2pq = % heterozygous individualsFrom the given, we haveq2 = 21%Simply taking the square root,q = 4.58%</span>