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3 years ago

How many solutions does this linear system have?

Mathematics

1 answer:

gayaneshka [121]3 years ago

4 0

Answer:

One solution: (2.5,0)

Step-by-step explanation:

We can use substitution for the solution. Substitute y=2x-5 to -8x-4y=-20 so that you end up with -8x-8x+20=-20. Next you want to add like terms which will be -16x+20=-20, next you want isolate x by subtracting 20 from both sides and leaves you with -16x=-40. Divide -16 on both sides to fully isolate x and will leave you with x=2.5. Now substiture in 2.5 for x in y=2x-5 to get y=2(2.5)-5 which will then lead to y=0.

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Solve for xxx. Write the smaller solution first, and the larger solution second.

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Answer:

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Step-by-step explanation:

We have been given an equation $x^2+3x-10=0$ . We are asked to find the solutions of our given equation.

We will use splitting the middle term method to solve quadratic equation.

We will split middle term of our given equation into parts such that whose product is $-10$ and whose sum is 3.

We know that such two numbers are $5\text{ and }-2$ .

$x^2+5x-2x-10=0$

$(x^2+5x)+(-2x-10)=0$

$x(x+5)-2(x+5)=0$

$(x+5)(x-2)=0$

Using zero product property, we will get:

$(x+5)=0\text{ or }(x-2)=0$

$x+5=0\text{ or }x-2=0$

$x=-5\text{ or }x=2$

Therefore, the solutions for our given equation are $x=-5\text{ or }x=2$ .

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