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2 years ago

Is a triangle with angle measures 40,30,and 120 possible?

2 answers:

7 0

It's impossible to have this be the case in any triangle, as the angles can be added to make 190. For it to be a triangle, it needs to be 180.

Schach [20]2 years ago

5 0

No, it is nit possible to have any kind of triangle with these measurements.

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Aleks04 [339]

Answer:

Step-by-step explanation:

${(6x + 11)}^{o} = {(10x - 9)}^{o} \\ 11 + 9 = 10x - 6x \\ 20 = 4x \\ \frac{20}{4} = \frac{4x}{4} \\ 5 = x \\$

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m∠1 = (6x + 11)°

${(6x + 11)}^{o} \\ 6(5) + 11 \\ 30 + 11 \\ {41}^{o} \\$

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2 years ago

2. About how much is 123.1 do you weigh in pounds? Estimate if you don't know☺ Find an online converter and find out how many ki

Mama L [17]

Answer:

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Step-by-step explanation:

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2 years ago

What is the quotient of 6/7 divided by 3/14

bija089 [108]

Answer:

6/7 ÷ 3/14

= 6/7 × 14/3

= 2/7 × 14 (we cancelled 3 with 6)

= 2×2 (we cancelled 7 with 14)

= 4

hope it helps

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

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Firlakuza [10]

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3 years ago

Read 2 more answers

Given two points M & N on the coordinate plane, find the slope of MN , and state the slope of the line perpendicular to MN .

telo118 [61]

Answer:

Problem 1) $m = \dfrac{1}{4}$ $slope_{perpendicular} = -4$

Problem 2) $m = \dfrac{1}{3}$ $slope_{perpendicular} = -3$

Step-by-step explanation:

$slope = m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$slope_{perpendicular} = \dfrac{-1}{m}$

Problem 1) M(9,6), N(1,4)

$slope = m = \dfrac{6 - 4}{9 - 1} = \dfrac{2}{8} = \dfrac{1}{4}$

$slope_{perpendicular} = \dfrac{-1}{\frac{1}{4}} = -4$

Problem 2) M(-2,2), N(4,-4)

$slope = m = \dfrac{4 - 2}{4 - (-2)} = \dfrac{2}{6} = \dfrac{1}{3}$

$slope_{perpendicular} = \dfrac{-1}{\frac{1}{3}} = -3$

4 0

3 years ago