Answer:
Part 1) The length of the longest side of ∆ABC is 4 units
Part 2) The ratio of the area of ∆ABC to the area of ∆DEF is 
Step-by-step explanation:
Part 1) Find the length of the longest side of ∆ABC
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor
The ratio of its perimeters is equal to the scale factor
Let
z ----> the scale factor
x ----> the length of the longest side of ∆ABC
y ----> the length of the longest side of ∆DEF
so

we have


substitute

solve for x


therefore
The length of the longest side of ∆ABC is 4 units
Part 2) Find the ratio of the area of ∆ABC to the area of ∆DEF
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z ----> the scale factor
x ----> the area of ∆ABC
y ----> the area of ∆DEF

we have

so


therefore
The ratio of the area of ∆ABC to the area of ∆DEF is 
Oh! I answered this question last week! Don't know if it was the same exact one, but whatever. So first cut the number of pages in Kate's report in half, then add 5 to that. So, (14÷2)+5
You do distance over time to get the rate, so you'd do 27/2= 13.5mph then divide that in half since you're asking for the distance traveled in half that hour so you do 13.5/2 and you get 6.75 miles traveled in half and hour.
This is the concept of areas of solid materials; the surface area of the cylinder whose radius is 2.5 cm and lateral area is 20 pi cm^2 will be: Surface area of cylinder is given by:
SA=(area of cyclic sides)+(lateral area)
SA=2πr^2+πrl
Area of the cyclic sides will be:
Area=2πr^2
=2*π*2.5^2
=12.5π cm^2
The lateral area is given by:
Area=20π cm^2
Therefore the surface area of cylinder will be:
SA=(12.5π+20π) cm^2
SA=32.5π cm^2
The answer is 32.5π cm^2