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umka21 [38]
4 years ago
13

HURRRRRRYYYYYYY 1 QUESTION EXPERTS/ACE HELP QUICK!!!!!

Mathematics
1 answer:
Pepsi [2]4 years ago
5 0
The last answer is correct x^5/6 + 2x^7/3
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If a car moves 640 miles in 11 hours what is the average rate of the car?
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Divide the distance by the amount of time it traveled:
640/11 = 58.18 Mph 
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Simplify the following expressions by factoring using the greatest common factor:
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Marcie's gross pay is $360.00 After deductions of 10% what is her net pay?
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8 0
3 years ago
The population of a local species of bees can be found using an infinite geometric series where a1=860 and the common ratio is 1
erma4kov [3.2K]
a_1=860
a_2=\dfrac{a_1}5
a_3=\dfrac{a_2}5=\dfrac{a_1}{5^2}
\vdots
a_n=\dfrac{a_{n-1}}5=\dfrac{a_{n-2}}{5^2}=\cdots=\dfrac{a_1}{5^{n-1}}

The kth partial sum is

\displaystyle S_k=\sum_{n=1}^ka_n=\sum_{n=1}^k\frac{a_1}{5^{n-1}}
S_k=a_1\left(1+\dfrac15+\dfrac1{5^2}+\cdots+\dfrac1{5^{k-2}}+\dfrac1{5^{k-1}}
\dfrac15S_k=a_1\left(\dfrac15+\dfrac1{5^2}+\dfrac1{5^3}+\cdots+\dfrac1{5^{k-1}}+\dfrac1{5^k}\right)

\implies S_k-\dfrac15S_k=a_1\left(1-\dfrac1{5^k}\right)
\dfrac45 S_k=860\left(1-\dfrac1{5^k}\right)
S_k=1075-\dfrac{1075}{5^k}

As k\to\infty, we're left with

\displaystyle\sum_{n=1}^\infty a_n=\lim_{k\to\infty}\left(1075-\frac{1075}{5^k}\right)=1075

which is the upper limit to the population of the bees.
4 0
3 years ago
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